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n 3
n 2
u 2
u 2
u 2
+
+
+
+
n 2
n 2
n 2
n 3
n 3
n 3
=
A
n 1
u 3
u 3
u 3
n 1
n
n 1
1
u 1
u 1
u 1
Fig. 9.5 Illustration of the CP-decomposition for a 3-mode tensor A. The dashed lines indicate the
boundaries of a rank-k factorization
Here, the symbol “
” represents the outer vector product, i.e., each element of a
¼ v i i∈ n k , which is called a CP rank-1-
tensor , is the product of its corresponding vector elements
tensor A ¼ v 1
v d with vectors v k
...
a i 1 , ... , i d ¼ v i 1 v i 2 ...
v i d :
Thus, we may write ( 9.7 ) component-wise:
a i 1 , ...i d ¼ X
t
u i 1 , j u i d , j :
1
Therefore, ( 9.7 ) tells us that each CP-tensor may be represented by a sum of
rank-1 tensors (Fig. 9.5 ).
For d ¼ 2, the HOSVD, i.e., the “classical” SVD, coincides with a
CP-decomposition, since the “core tensor” S k in ( 8.14 ) is a diagonal matrix. Though
it is not the identity matrix, we may multiply the diagonal values into the matrices
of singular vectors, for example, into V k .
Example 9.7 The rank-2 approximation from Example 8.4 may be written as a sum
of two rank-1 tensors:
0
@
1
A
,
10
:
3
0
:
23
2
:
76 9
:
65
5
:
17
A k ¼XY ¼
0
:
2 0
:
7
0
:
69 6
:
61
:
65 0
:
14
:
1 0
:
0
7
0
@
1
A
0
@
1
A
1
0
3
0
0
:
¼
:
2
ð Þ
| {z }
u ðÞ
0
:
23 2
:
76 9
:
65 5
:
17
þ
:
7
ð Þ
| {z }
u ðÞ
0
:
69 6
:
61
:
65 0
:
14
0
:
1
0
:
7
T
T
| {z }
u 1
| {z }
u 1
¼u 1
u 1
þu 2
u 2 :
 
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