Biomedical Engineering Reference
In-Depth Information
and
0
a
d U
=
l
(
t
)
dt
+
l
(
t
)
dW t
t 1 t 2
(
)
>
with W t being Brownian motion, l
t
is the control signal, and a
0 (see Section
1.3). Basically, under the rate coding assumption, a
=
1
/
2 corresponds to Poisson
inputs [57, 77] (also see Section 1.3).
We call
a
<
1
/
2 sub-Poisson inputs ,and
a
>
2 supra-Poisson inputs .
Here is the control problem.
1
/
2a
(
) ∈ L
[
,
+
]
For a fixed, deterministic time T ,findl
s
0
T
R
which minimizes
T
+
R
var
(
x 1 (
t
))
dt
(1.19)
T
subject to the constraint
E
[
x 1 (
T
)] =
D for t
[
T
,
T
+
R
]
(1.20)
The meaning is clear. Equation (1.20) ensures that at time T , the saccadic movement
stops at the position D and keeps there for a while, i.e., from time T to T
+
R .During
the time interval
[
T
,
T
+
R
]
, it is required that the fluctuation is as small as possible
(Equation (1.19)).
When a
>
1
/
2, define
exp
exp
t 1 t 2
t 2
t 2 (
t 1 (
b 12 (
t
s
)=
t
s
)
t
s
)
t 1
t 1 exp
t 2 exp
t 1 t 2
t 2
t 1 (
t 2 (
b 22 (
t
s
)=
t
s
)
t
s
)
,
t 1
so the solution of the optimal control problem is
m 2 exp s t 2
m 1 exp t 1
) sgn m 1 exp s t 1
m 2 exp t 2
/ (
1
2a
1
+
+
l
(
s
)=
dt 1 / ( 2a
1
)
T
+
R
b 12 (
t
s
)
0
(1.21)
with m 1 ,
m 2 being given by
D t 2 exp t 2
exp t 2
T
A
(
s
)
=
·
ds
B
(
s
)
D t 1 exp t 1
0
(1.22)
exp t 1
T
A
(
s
)
=
·
ds
.
B
(
s
)
0
with
m 1 exp t 1
m 2 exp s t 2
) sgn m 1 exp s t 1
m 2 exp t 2
1
/ (
2a
1
A
(
s
)=
+
+
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