Biomedical Engineering Reference
In-Depth Information
vanishingly small makes the approximation in Equations
4.11 and 4.13 exact and we can assume that the contribution to the concentration at
a point, y
Making
r ,
δ θ
and
δ φ
=(
r
,
0
,
0
)
, from the volume X is as if from a point source at the point:
=(
, θ , φ )
x
. Inspecting Equation 4.7 we see that the concentration depends on the
time after synthesis and the distance between x and y ,
r
. Substituting this
and our strength/second term, S X , from Equation 4.13 into Equation 4.7 we obtain
the concentration of NO at y due to x at a time t after synthesis:
x
y
ex p
e λ
r 2 sin
2
Q
drd
d
x
y
t
C P (
x
y
,
t
)=
(4.14)
8
( π
Dt
)
3
/
2
4 Dt
Now, to get the concentration at y due to the whole sphere we must sum up the
contributions from all the points x
=(
r
, θ , φ )
inside the sphere, M , (i.e., 0
r
a ;0
θ π
and 0
φ
2
) as shown below:
)= x M C P ( x y , t )
C S (
a
,
r
,
t
(4.15)
exp
(4.16)
a
π
r 2 sin
2
Q
x
y
=
8
( π
Dt
)
3 / 2
4 Dt
0
0
0
e λ
t drd
·
d
(4.17)
Using:
2
r 2
r 2
x
y
=
+
2 rr cos
(4.18)
and noting that there is radial symmetry so that the concentration at any point z
=
(
r
, θ , φ )
at a distance of r from the origin is equal to the concentration at y
=(
r
,
0
,
0
)
,
we therefore obtain:
t 1
2
erf a
erf a
+
r
2 Dt
r
2 Dt
e λ
C S (
a
,
r
,
t
)=
Q
+
Dt
π
exp (
exp (
2
2
1
r
a
r
)
a
+
r
)
(4.19)
4 Dt
4 Dt
where:
x
exp
u 2 du
2
π
erf
(
x
)=
(4.20)
0
for the concentration at a distance r from the centre of a solid sphere of radius a at
a time t after synthesis. This leads naturally to the solution for a hollow sphere of
inner radius a and outer radius b :
C H (
a
,
b
,
r
,
t
)=
C S (
b
,
r
,
t
)
C S (
a
,
r
,
t
)
(4.21)
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