Moving Toward Object-Oriented Programming - Beginning Java Programming: The Object-Oriented Approach - page 113

Memory Address
#000023

Memory Address
#000025

Memory Address
#000029

Test t int[] t.array anintArray = new

int[] {100,200,300};
(Memory address
reference is overwritten.)

23 24 25 26 27 28 29 30 31

t object
(general info, such
as length of
following variable
addresses)

array var
=
000025

array[0]
= 1

array[1]
= 2

array[2]
= 3

anintArr
ay var =
000029

anintArr
ay[0] =
100

anintArray
ay[1] =
200

anintArray
ay[2] =
300

figure 4-7

Note Again, it's important to take special care when dealing with Strings.
Strings are a non‐primitive type, meaning that you might try to write the fol-
lowing code:
class Test {
String a = "a";

static void changeString(String s) {
s = "b";
}

public static void main(String[] args) {
Test t = new Test();
System.out.println("a is: "+t.a);
Test.changeString(t.a);
System.out.println("a is now: "+t.a);
}
}

But see that the changes you make to the String are not reflected in the mem-
ber variable. The reason for this is simple. Remember that assigning (new) val-
ues to a String will always create a new String object. This code is thus equal
to writing:

class Test {
String a = new String("a");

continues