Digital Signal Processing Reference
In-Depth Information
dg
(
x
)
dx
2.
≤
0(
g
(
x
) monotone non increasing);
d
2
g
(
x
)
3.
≥
0(
g
(
x
) convex).
dx
2
Then
f
(
x
) is Schur-convex on
D
(i.e., for
x
0
≥
x
1
≥
...
≥
x
P−
1
).
♦
Proof.
Throughout the proof remember that the condition
x
0
≥ x
1
≥ ...≥
x
P−
1
is assumed. The notation
dg
(
x
k
)
/dx
denotes the derivative of
g
(
x
)
evaluated at
x
k
.
Since
d
2
g
(
x
)
/dx
2
≥
0, we have
dg
(
x
0
)
dx
≥
dg
(
x
1
)
dx
≥ ...≥
dg
(
x
P
−
1
)
dx
.
Using
dg
(
x
)
/dx
≤
0 we therefore get
dg
(
x
0
)
dx
≤−
dg
(
x
1
)
dx
≤
dg
(
x
P
−
1
)
dx
0
≤−
...
≤−
.
We now combine this with the first condition of the corollary:
0
≤
a
0
≤
a
1
≤
...
≤
a
P−
1
.
Since
a
k
and
dg
(
x
k
)
/dx
are non-negative we conclude from the preceding
two sets of inequalities that
−
dg
(
x
0
)
dx
≤−
dg
(
x
1
)
dx
≤
dg
(
x
P
−
1
)
dx
0
≤−
a
0
a
1
...
≤−
a
P−
1
which is equivalent to
dg
(
x
0
)
dx
≥
dg
(
x
1
)
dx
≥
dg
(
x
P
−
1
)
dx
0
≥
a
0
a
1
...
≥
a
P−
1
The function (21.36) therefore has the form (21.35) (just set
g
k
(
x
)=
a
k
g
(
x
))
and satisfies all the conditions of Theorem 21.4. It is therefore a Schur-
convex function in
D
.
For example, let
g
(
x
)=
1
x
p
,
p>
0
.
Then, for
x>
0
,
<
0and
d
2
g
(
x
)
dx
2
dg
(
x
)
dx
=
−
p
x
p
+1
=
p
(
p
+1)
x
p
+2
>
0
.
Applying Corollay 21.1 it therefore follows that
P−
1
a
k
x
k
f
(
x
)=
,
p>
0
(21
.
37)
k
=0
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