Digital Signal Processing Reference
In-Depth Information
20.3.1 Definitions
|
2
=
zz
∗
this is
not analytic in the variable
z
(the presence of
z
∗
makes it non-analytic [Churchill
and Brown, 1984]). So
dh
(
z
)
/dz
does not exist. However, imagine for a moment
that
z
and
z
∗
denote two separate, independent, variables and define the two-
variable function
|
2
.
Since
To motivate the idea consider the example
h
(
z
)=
|
z
|
z
g
(
z, z
∗
)=
zz
∗
.
We can differentiate with respect to
z
by holding
z
∗
constant, and vice versa.
That is, we can define the partial
derivatives
∂g
(
z, z
∗
)
∂z
∂g
(
z, z
∗
)
∂z
∗
=
z
∗
and
=
z.
A subtle point about notation.
We know that
z
and
z
∗
are not independent;
knowing one we can find the other. However, given the original function
h
(
z
), if
we replace all occurrence of
z
with the notation
z
1
and all occurrence of
z
∗
with
z
2
, then the two-variable function
g
(
z
1
,z
2
) can certainly be differentiated with
respect to each variable separately. Instead of using the new notations
z
1
and
z
2
we simply carry on with
z
and
z
∗
.
The fact that any
h
(
z
) can be expressed
uniquely as
g
(
z, z
∗
) is explained in a footnote in Sec. 20.3.2.
The usefulness of this “brave” definition will become clear as soon as some
of its properties are established. For now, just consider another example: let
h
(
z
)=2Re[
z
]. This is not analytic because
h
(
z
)=
z
+
z
∗
.So
dh
(
z
)
/dz
does not
exist. Define the two-variable function
g
(
z, z
∗
)=
z
+
z
∗
.
Then
∂g
(
z, z
∗
)
∂z
∂g
(
z, z
∗
)
∂z
∗
= 1
and
=1
.
Finally consider the simple example
h
(
z
)=
z.
In this case
g
(
z, z
∗
)=
z
so that
∂g/∂z
= 1 and
∂g/∂z
∗
=0
.
Thus
∂z
∂z
= 1
∂z
∂z
∗
and
=0
.
(20
.
18)
Similarly,
∂z
∗
∂z
∂z
∗
∂z
∗
= 0
and
=1
.
(20
.
19)
More generally,
if
g
(
z, z
∗
) is free from
z
∗
then
∂g/∂z
∗
=0
,
(20
.
20)
if
g
(
z, z
∗
) is free from
z
then
∂g/∂z
=0
.
(20
.
21)
In complex variable theory the derivative
∂z
∗
/∂z
is undefined because
z
∗
is not
analytic. Observe however that the meaning of the notation here is different.
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