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=↓ (S 1
( S 1 S 2 )
( from ↓=
((
1. Γ(S 1
S 2 )
S 2 )
=↓
=
id W )
=↓
)
S 1
(
) S 2 )
=
S 1 ∪↓ S 2 )
(
=
Γ(ΓS 1
ΓS 2 )
F
(W) .
Thus, Γ is a homomorphism for join operators, and, analogously,
2. Γ(S 1
=
Γ(ΓS 1
=
S 2 )
ΓS 2 )
(from the fact that Γ is a closure operator)
(W) .
Thus, Γ is a homomorphism for meet operators. For each a W ,theset
=
ΓS 1
ΓS 2 F
a is
closed, so that Γ( a) =↓ a , and for any S H(W) , a,b W ,
3. S ∩↓ a ⊆↓ b iff ΓS ∩↓ a ⊆↓ b .
(the implication from right to left is obvious, based on the closure property of
Γ , S ΓS ; for the implication from left to right, we can use the monotonicity
property of the closure operator Γ , and hence if S
∩↓
a
⊆↓
b then Γ(S
a)
=
( from 2 .)
=
ΓS
Γ(
a)
=
ΓS
∩↓
a
Γ(
b)
=↓
b .
Let us show that the complete lattice (
,W) is also dis-
tributive and hence an r.p.c. lattice, so that we can define the (relative) pseudo-
complements
F
(W),
,
{
0
}
and ¬
. In fact, for any S 1 =
ΓS 1 =↓
a,S 2 =
ΓS 2 =↓
b,S 3 =
ΓS 3 F
(W)
H(W) ,
4.
Γ (Γ S 1
ΓS 3
Γ
(S 1
S 2 ,S 3 )
=
Γ
(Γ S 1
ΓS 2 ,ΓS 3 )
=
ΓS 2 )
(by the distributivity of
and
)
ΓS 3 )
(from the homomorphism property 1.)
Γ (Γ S 1
=
ΓS 3 )
(Γ S 2
=
Γ(ΓS 1
Γ(ΓS 2
ΓS 3 )
ΓS 3 )
=
Γ(S 1
S 3 )
Γ(S 2
S 3 )
=
Γ
(S 1 ,S 3 )
Γ
(S 2 ,S 3 ).
5.
Γ (S 1 ,S 2 ) S 3 = Γ (S 1 ,S 2 ) ΓS 3 = Γ(S 1 S 2 ) ΓS 3
(from the homomorphism property 1.)
= Γ (S 1 S 2 ) S 3
(by the distributivity of
and
)
Γ (S 1
S 3 ) =
(S 1
S 3 ) .
=
S 3 )
(S 2
Γ
S 3 ),(S 2
From the fact that the complete distributive lattice of hereditary subsets H (W) sat-
isfies the infinite distributivity law (so it is a Heyting algebra), from this homomor-
phism (an analogous proof as for points 3 and 4), also the complete distributive
lattice (
) of closed hereditary subsets satisfies the infinite distributive law,
and, consequently, it is a Heyting algebra with:
6.
F
(W),
b
(
a)
(
b)
=
Γ
c
F
(W)
|↓
c
∩↓
a
⊆↓
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