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Example 23 Let us consider a number of “conceptualizations” of complex mor-
phisms in Theorem 4 , expressed by the functor T e =
(T e ,T e )
:
−→
( DB
DB )
DB :
1. The case when f = f 1 + f 2 : A 1 + A 2 B 1 + B 2 ,g = g 1 + g 2 : C 1 + C 2 D 1 +
D 2 ,h = h 1 + h 2 : A 1 + A 2 C 1 + C 2 and k = k 1 + k 2 : B 1 + B 2 D 1 + D 2 ,
are such that k 1
f 1 =
g 1
h 1 and k 2
f 2 =
g 2
h 2 , so that we have the arrow
(h 1 +
h 2 ;
k 1 +
k 2 )
:
J(f)
J(g) and hence
: f 1 + f 2
T e (h 1 +
h 2 ;
k 1 +
k 2 )
=
T e (h 1 ,k 1 )
+
T e (h 2 ,k 2 )
g 1 +
g 2 .
2. The case when f
=[
f 1 ,f 2 ]:
A 1 +
A 2
B,g
:
C
D,h
=[
h 1 ,h 2 ]:
A 1 +
A 2
C and k
:
B
D are such that k
f 1 =
g
h 1 and k
f 2 =
g
h 2 , so that
we have the arrow (
[
h 1 ,h 2 ];
k)
:
J(f)
J(g) and hence
T e [
k = T e (h 1 ,k),T e (h 2 ,k) : f 1 + f 2
h 1 ,h 2 ];
g.
3. The case when f
:
A
B,g
=[
g 1 ,g 2 ]:
C 1 +
C 2
D,h
=
h 1 ,h 2 :
A
C 1 +
C 2 and k
:
B
D are such that k
f
=
g 1
h 1 and k
f
=
g 2
h 2 , so that
we have the arrow (
h 1 ,h 2 ;
k)
:
J(f)
J(g) and hence
T e
k = T e (h 1 ,k),T e (h 2 ,k) : f
h 1 ,h 2 ;
g 1 +
g 2 .
4. The case when f
=
f 1 ,f 2 :
A
B 1 +
B 2 ,g
=
g 1 ,g 2 :
C
D 1 +
D 2 ,h
:
A
C and k
=
k 1 +
k 2 :
B 1 +
B 2
D 1 +
D 2 are such that k 1
f 1 =
g 1
h and
k 2
f 2 =
g 2
h , so that we have the arrow (h
;
k 1 +
k 2 )
:
J(f)
J(g) and hence
: f
T e (h
;
k 1 +
k 2 )
=
T e (h,k 1 ),T e (h,k 2 )
g 1 +
g 2 .
5. The case when f
=
f 1 ,f 2 :
A
B 1 +
B 2 ,g
:
C
D,h
=
h 1 ,h 2 :
A
C
=[
k 1 ,k 2 ]:
B 1 +
B 2
D are such that k 1
f 1 =
h 1 and k 2
f 2 =
and k
g
g
h 2 , so that we have the arrow (
h 1 ,h 2 ;[
k 1 ,k 2 ]
)
:
J(f)
J(g) and hence
T e ( h 1 ,h 2 ;[ k 1 ,k 2 ] ) =[ T e (h 1 ,k 1 ),T e (h 2 ,k 2 ) ]: f 1 + f 2 g .
But also more complex cases:
6. The case when f
=[
f 1 ,f 2 ]:
A 1 +
A 2
B,g
=[
g 1 ,g 2 ]:
C 1 +
C 2
D,h
=
h 1 +
h 2 :
A 1 +
A 2
C 1 +
C 2 and k
:
B
D are such that k
f 1 =
g 1
h 1 and
k
f 2 =
g 2
h 2 , so that we have the arrow (h 1 +
h 2 ;
k)
:
J(f)
J(g) and hence
T k
f 1 ,f 2 ]
T e (h 1 +
h 2 ;
=
in g 1 , in g 2
◦[
(in f 1 +
k)
in f 2 )
= T e (h 1 ,k),in g 2
in f 1 ,
T(k
f 1 )
in g 1
in f 2 ,T e (h 2 ,k) : f 1 + f 2
T(k
f 2 )
g 1 +
g 2 .
7. The case when f = f 1 ,f 2 : A 1 + A 2 B,g =[ g 1 ,g 2 ]: C 1 + C 2 D,h =
h 1 ,h 2 : A 1 + A 2 C 1 + C 2 and k =[ k 1 ,k 2 ]: B 1 + B 2 D 1 + D 2 , so that
we obtain
T e h 1 +
k 1 ,k 2 ]
= T e (h 1 ,k 1 ), in g 1
h 2 ;[
in f 2 ,
T(k 1
f 1 )
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