Database Reference
In-Depth Information
Example 23
Let us consider a number of “conceptualizations” of complex mor-
phisms in Theorem
4
, expressed by the functor
T
e
=
(T
e
,T
e
)
:
↓
−→
(
DB
DB
)
DB
:
1. The case when
f
=
f
1
+
f
2
:
A
1
+
A
2
→
B
1
+
B
2
,g
=
g
1
+
g
2
:
C
1
+
C
2
→
D
1
+
D
2
,h
=
h
1
+
h
2
:
A
1
+
A
2
→
C
1
+
C
2
and
k
=
k
1
+
k
2
:
B
1
+
B
2
→
D
1
+
D
2
,
are such that
k
1
◦
f
1
=
g
1
◦
h
1
and
k
2
◦
f
2
=
g
2
◦
h
2
, so that we have the arrow
(h
1
+
h
2
;
k
1
+
k
2
)
:
J(f)
→
J(g)
and hence
:
f
1
+
f
2
→
T
e
(h
1
+
h
2
;
k
1
+
k
2
)
=
T
e
(h
1
,k
1
)
+
T
e
(h
2
,k
2
)
g
1
+
g
2
.
2. The case when
f
=[
f
1
,f
2
]:
A
1
+
A
2
→
B,g
:
C
→
D,h
=[
h
1
,h
2
]:
A
1
+
A
2
→
C
and
k
:
B
→
D
are such that
k
◦
f
1
=
g
◦
h
1
and
k
◦
f
2
=
g
◦
h
2
, so that
we have the arrow
(
[
h
1
,h
2
];
k)
:
J(f)
→
J(g)
and hence
T
e
[
k
=
T
e
(h
1
,k),T
e
(h
2
,k)
:
f
1
+
f
2
→
h
1
,h
2
];
g.
3. The case when
f
:
A
→
B,g
=[
g
1
,g
2
]:
C
1
+
C
2
→
D,h
=
h
1
,h
2
:
A
→
C
1
+
C
2
and
k
:
B
→
D
are such that
k
◦
f
=
g
1
◦
h
1
and
k
◦
f
=
g
2
◦
h
2
, so that
we have the arrow
(
h
1
,h
2
;
k)
:
J(f)
→
J(g)
and hence
T
e
k
=
T
e
(h
1
,k),T
e
(h
2
,k)
:
f
h
1
,h
2
;
→
g
1
+
g
2
.
4. The case when
f
=
f
1
,f
2
:
A
→
B
1
+
B
2
,g
=
g
1
,g
2
:
C
→
D
1
+
D
2
,h
:
A
→
C
and
k
=
k
1
+
k
2
:
B
1
+
B
2
→
D
1
+
D
2
are such that
k
1
◦
f
1
=
g
1
◦
h
and
k
2
◦
f
2
=
g
2
◦
h
, so that we have the arrow
(h
;
k
1
+
k
2
)
:
J(f)
→
J(g)
and hence
:
f
T
e
(h
;
k
1
+
k
2
)
=
T
e
(h,k
1
),T
e
(h,k
2
)
→
g
1
+
g
2
.
5. The case when
f
=
f
1
,f
2
:
A
→
B
1
+
B
2
,g
:
C
→
D,h
=
h
1
,h
2
:
A
→
C
=[
k
1
,k
2
]:
B
1
+
B
2
→
D
are such that
k
1
◦
f
1
=
◦
h
1
and
k
2
◦
f
2
=
and
k
g
g
◦
h
2
, so that we have the arrow
(
h
1
,h
2
;[
k
1
,k
2
]
)
:
J(f)
→
J(g)
and hence
T
e
(
h
1
,h
2
;[
k
1
,k
2
]
)
=[
T
e
(h
1
,k
1
),T
e
(h
2
,k
2
)
]:
f
1
+
f
2
→
g
.
But also more complex cases:
6. The case when
f
=[
f
1
,f
2
]:
A
1
+
A
2
→
B,g
=[
g
1
,g
2
]:
C
1
+
C
2
→
D,h
=
h
1
+
h
2
:
A
1
+
A
2
→
C
1
+
C
2
and
k
:
B
→
D
are such that
k
◦
f
1
=
g
1
◦
h
1
and
k
◦
f
2
=
g
2
◦
h
2
, so that we have the arrow
(h
1
+
h
2
;
k)
:
J(f)
→
J(g)
and hence
T
k
f
1
,f
2
]
◦
T
e
(h
1
+
h
2
;
=
in
g
1
, in
g
2
◦
◦[
(in
f
1
+
k)
in
f
2
)
=
T
e
(h
1
,k),in
g
2
◦
in
f
1
,
◦
◦
T(k
f
1
)
in
g
1
◦
in
f
2
,T
e
(h
2
,k)
:
f
1
+
f
2
→
T(k
◦
f
2
)
◦
g
1
+
g
2
.
7. The case when
f
=
f
1
,f
2
:
A
1
+
A
2
→
B,g
=[
g
1
,g
2
]:
C
1
+
C
2
→
D,h
=
h
1
,h
2
:
A
1
+
A
2
→
C
1
+
C
2
and
k
=[
k
1
,k
2
]:
B
1
+
B
2
→
D
1
+
D
2
, so that
we obtain
T
e
h
1
+
k
1
,k
2
]
=
T
e
(h
1
,k
1
), in
g
1
◦
h
2
;[
in
f
2
,
T(k
1
◦
f
1
)
◦