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T π x i e ( _ ) j /r i,j 1 j k A |
q i
=
O r i, 1 ,...,r i,k ,r i is equal to e
( _ )( t i )
M AB
= f
TA.
From the fact that this information flux is transferred into B , f
TB , so that f
TA TB , i.e., by Definition 19 , f A B . Each arrow is a composition of a
number of atomic arrows and the intersection of closed objects (their information
fluxes) is always a closed object.
If f : 1 j m A j 1 i k B i is a complex morphism with a set of more than
one point-to-point arrow in f
f
, f ji
then, for each f ji :
A j
B i
TA j
TB i .
Hence f
f
f
B and f
(from Definition 22 , f
), so that f
A
B . From Lemma 9 , id A =
A
TA and, from a Definition 19 and T(TA)
=
TA ,
id A id B
and we will show that it can be internally represented in DB by a monomorphism
in
= id A id B . Thus, we obtain the PO relation f
A
B
=
TA
TB
id A id B . The fact that in, in A and in B are the morphisms defined by
Theorem 1 and hence they can be obtained from particular schema mappings and a
given R-algebra α will be shown in Theorem 4 .
Let us consider a morphism f
: f
: 1 j m A j 1 i k B i , k,m
1, with point-
f
: f
to-point (simple) arrows (f ji : A j B i )
. Let us define the morphism in
in
f ji }: f ji
TA
TB with
={
in ji ={
id R :
R
R
|
R
TA j
TB i |
(f ji :
f
f
in
: f ji
A j
B i )
}
. Thus, there is a bijection σ
:
with in ji =
σ(f ji )
in
f
TA j TB i and in jk = f jk for any ptp arrow, and hence in
f .
: 1 l n X l f of morphisms (with (g i,ji :
X l f ji )
For each pair g,h
g
X l f ji )
T f ji =
h
=∅
and (h l,ji :
=∅
so that, from Proposition 6 ,
g l,ji
f ji and h l,ji
T f ji = f ji and hence σ(f ji )
in
g
in
h
g l,ji
and σ(f ji )
h l,ji
)
in
g
=
in
h
such that in
.
Thus, they have the same ptp arrows, that is, σ(f ji ) g l,ji = σ(f ji ) h l,ji : X l
TA j
g
=
in
h
:
X
B , i.e., from point 3 of Definition 23 ,
TB i so that they have the same fluxes, i.e.,
σ(f ji )
g l,ji =
σ(f ji )
h l,ji .
g l,ji = σ(f ji )
g l,ji = f ji
However,
σ(f ji )
g l,ji =
g l,ji and, analogously,
σ(f ji )
h l,ji = f ji h l,ji = h l,ji so that h l,ji =
g l,ji , i.e., ptp arrows h l,ji =
g l,ji :
X l f ji are equal. This holds for all ptp arrows in g and h so that g
=
h . That is,
for each g,h such that in
g =
in
h : X B , we obtained that g = h , so that
: f
id A id B is a monomorphism and, analogously,
(i)
in
in A : f
id A =
TA and in B : f
id B =
(ii)
TB .
Claim 2. Let us show that for any two simple objects A and B , TA TB implies
the existence of a monomorphism in TA :
TA
TB .
If TA
TB then we have a morphism f
={
id R :
R
R
|
R
TA
}:
TA
TB with f
TA . Then, from (ii), we have a monomorphism in TA : f
=
id TB =
TB so, by substituting f by TA , we obtain in TA :
T(TB)
=
TA
TB .
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