Civil Engineering Reference
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Du 1 u 2
Dt
dU 1
p
ρ
1
ρ
u 2
x 1 +
u 1
=−
u 2 u 2
dx 2
u 1
u 2 u 2 +
+
p
x 2
x 2
P 12
Τ 12
π 12
2 u 1 u 2
ν
u 1
u 2
[2.9]
+ ν
x 2
2
x 2
x l
x l
D 12
ε 12
We ca n cl early see that P 12
0 . This suggests that, on
<
average, u 1 u 2
0 if we consider the production term to be
dominant. Figure 2.1 illustrates the mechanism of inter-
component transfer for a flow which is homogeneous in
directions x 1 an d x 3 , non homogeneous in x 2 and subject to a
shear effect dU dx 2 .
<
2.3. Models of return to isotropy
π 12 plays a crucial role in the mechanism of
transfe r. It s effect is to decrease the intensity of th e Re ynolds
stress u 1 u 2 . Indeed, we can envisage that
The correlation
u 1 u 2 , if we
accept the postulate that the pressure/velocity gradient
correlations essentially render the turbulence isotropic.
π
∝−
12
One of the simplest ways of looking at models of return to
isotropy is to consider homogeneous anisotropic turbu le nce,
which develops in the absence of any mean gradient
x j
[CHO 01]. 5 The transport equation [2.2] thus takes the exact
form
U i
uu
u
u
1
u
u
[2.10]
i
j
j
j
=
p
+
i
2
ν
i
t
ρ
x
x
x
x
i
j
l
l
5 A considerable number of studies have been published on this subject.
Readers can consult [CHO 01] for a variety of representative references.
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