Biomedical Engineering Reference
In-Depth Information
Next substitute (4.48) into (4.47) to obtain the least squared error (
I
), which is given
by (4.49).
M
n
=0
x
(
t
)
=
a
n
φ
n
(
t
)
(4.48)
x
(
t
)
n
(
t
)
2
t
2
M
n
=0
a
n
I
=
−
φ
dt
(4.49)
t
1
The next step is to find the set of estimators coefficients
a
n
that minimize the value
of the integral (least squared error) in (4.47). One method is to differentiate the least
squared error (
I
) with respect to each of the coefficients and set each derivative equal
to 0. There are other alternative procedures that may be used, but will not be discussed
in this chapter.
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