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(a)
(b)
0.31 nm
0.38 nm
2 nm
50 nm
(c)
(d)
0.39 nm
2 nm
50 nm
Figure 3.17 TEM images of fresh (a, b) and used (c, d) Pd 0 /CaF 2 catalysts for hydrodehalogenation
of CHClF 2 . (Reprinted with permission from [32] (2008) Elsevier Ltd.)
The two marked lattice distances correspond to two different phases. Within CaF 2 the
{111} lattice plane distance of d 111 ¼ 0.31(4) was determined and for the metallic Pd the
distance of the {100} lattice plane of d 100 ¼ 0.38(2). Only these two phases could be
detected in these and in other fresh samples investigated, giving evidence for the absence
of PdF 2 or PdCl 2 , all Pd is in the metallic state as had already derived from the XRD
patterns (see above). In case of the used catalyst (Figures 3.17 c and d) the lattice plane
distance of 0.39 nm does not rule out the possible formation of PdF 2 or PdO as result of the
highly corrosive reaction conditions [33].
Hydrodehalogenation, the selective replacement of halogen by hydrogen on saturated
halocarbons, depends on the strength of the C-X bond, the catalyst and the reaction
conditions. Thus, upon hydrodehalogenation of CHClF 2 C-C coupling products have
been observed using Ni catalysts [41], whereas only CH 3 F and CH 4 were obtained with
silica-supported Pd [42].
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