Chemistry Reference
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where all other matrix elements are zeros. Expanding this determinant with respect
to its last column we obtain a recursive relation
a
2
a
1
a
3
a
2
a
N
a
N 1
D
D
N 1
1
C
.
1/
N 1
a
1
b
N
.
/.
/:::.
D
D
N 1
C
a
N
b
N
D
N
/
completing the proof.
t
Two particular applications of identity (E.1) will be shown next.
Consider first the determinant with the simple structure
0
@
1
A
A
1
./ B
1
./ ::: B
1
./
B
2
./ A
2
./ ::: B
2
./
:
:
:
:
:
:
:
:
:
Det
D
det
:
(E.2)
:
:
:
B
N
./ B
N
./:::A
N
./
By introducing vectors
b
./
D
.B
1
./;:::;B
N
.//
T
;
1
T
D
.1;:::;1/ and the
diagonal matrix
D
./
D
diag.A
1
./
B
1
./;:::;A
N
./
B
N
.// we can rewrite
the determinant as
det
.
D
./
C b
./
1
T
/
D
det
.
D
./
det
.
I C D
1
./
b
./
1
T
/:
The first determinant is diagonal, the second has the special structure of (E.1) with
a D D
1
./
b
./ and
b
T
D
1
T
. So by using identity (E.1) we have
"
1
C
#
:
Y
N
X
N
B
k
./
A
k
./
B
k
./
Det
D
.A
k
./
B
k
.//
(E.3)
k
D
1
k
D
1
Consider next a special matrix
0
1
a
1
b
1
::: b
1
b
2
a
2
::: b
2
:
:
:
:
:
:
:
:
:
b
N
b
N
:::a
N
@
A
A D
:
(E.4)
The characteristic polynomial of this matrix can be determined by using relation
(E.3). Notice that
0
@
1
A
a
1
1
::: b
1
b
2
a
2
::: b
2
:
:
:
det
.
A
I
/
D
det
;
:
:
:
:
:
:
b
N
b
N
:::a
N
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