Chemistry Reference
In-Depth Information
Since all coefficients are positive by assuming again that Nh
1, the equilibrium is
locally asymptotically stable.
Consider next the case of T>0and m
D
1. Then (5.39) becomes the cubic
equation
3
T
2
C
2
.a.r
C
1/T
2
C
2T/
C
.1
C
2a.r
C
1/T/
C
a.1
C
r.1
Nh//
D
0: (5.40)
All coefficients are positive if Nh
1, and the Routh-Hurwitz stability criterion
shows that the roots have negative real parts if and only if
.a.r
C
1/T
2
C
2T/.1
C
2aT.r
C
1// > T
2
a.1
C
r.1
Nh//;
(5.41)
which is equivalent to the quadratic inequality
2.r
C
1/
2
.aT/
2
C
.aT/.4.r
C
1/
C
Nhr/
C
2>0:
(5.42)
The discriminant of the left hand side of (5.42) is
.4.r
C
1/
C
Nhr/
2
16.r
C
1/
2
D
Nhr.Nhr
C
8.r
C
1//:
The first factor is negative, so we have the following cases:
Case 1. If Nhr
C
8.r
C
1/ > 0, then the discriminant is negative, so (5.42) always
holds and the equilibrium is locally asymptotically stable.
Case 2. If Nhr
C
8.r
C
1/
D
0, then (5.42) holds for all values of aT except the sin-
gle root of the quadratic polynomial. So the equilibrium is locally asymptotically
stable unless
4.r
C
1/
Nhr
4.r
C
1/
2
4.r
C
1/
4.r
C
1/
2
1
r
C
1
D
1
C
8
Nh
:
aT
D
D
D
Case 3.
If Nhr
C
8.r
C
1/ < 0, then the quadratic polynomial (5.42) has two real
roots,
4.r
C
1/
Nhr
˙
p
Nhr.Nhr
C
8.r
C
1//
4.r
C
1/
2
.aT/
1;2
D
:
(5.43)
Since
4.r
C
1/
Nhr
D
.Nhr
C
8.r
C
1//
C
4.r
C
1/ > 0;
both roots are positive. Hence the equilibrium is locally asymptotically stable if
aT < .aT/
1
or aT > .aT/
2
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