Chemistry Reference
In-Depth Information
2
0
@ X
l
1
3
x .t/ C ˇ S Z t
0
4 r k
A x .t/
5 ;
x .t/ D a k
w .t s;T;m/S ı .s/ds
¤
k
(4.60)
X
N
S ı .t/ D
x .t/ S S ı .t/;
(4.61)
l
D
1
where a k D ˛ 0 k .0/;r k D R 0 k at the equilibrium, and x ;S ı are respectively the
deviations of x k , S from their equilibrium levels. Seeking solutions in the form of
x .t/ D
u k e t
v e t , substituting these functions into (4.60)-(4.61)
and S ı .t/ D
and letting t !1 we have
u l C a k r k ˇ S Z 1
0
w .s;T;m/e s ds v ;
D a k r k X
l
. C a k / u k
(4.62)
¤
k
X
N
. C S / v D
u l :
(4.63)
l
D
1
Nonzero solutions for u k .1 k N/and v exist if and only if the determinant of
the matrix
0
1
. C a 1 / 1 r 1
a 1 r 1
a 1 r 1 ˇ S I./
@
A
a 2 r 2
. C a 2 /
a 2 r 2
a 2 r 2 ˇ S I./
: : :
a N r N
;
a N r N
. C a N /a N r N ˇ S I./
1
1
1
. C S /
is zero, where
T
p C 1 .mC1/
I./ D
;
with
( 1 if m D 0;
m if m 1:
p D
Notice that in the special case of T D 0 (no time delay is present) this determinant
reduces to the characteristic polynomial of the Jacobian of the model (4.31)-(4.32)
since I./ D 1 in this case. In the general case of T>0we follow a similar path
to that used in deriving equation (4.58) given earlier in this section. The (4.62) and
(4.63) can be rewritten as
a k r k U D a k r k ˇ S I./ v C . C a k C a k r k / u k
(4.64)
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