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Let us compute the sum of weight coefficients of elements with indexes
i
=
1
v
from the formula (4.7):
(
)
v
v
2
k
i
+
1
2
k
+
2
k
2
ν
+
2
2
k
ν
+
1
ω
=
=
ν
=
ν
.
(4.13)
(
)
(
)
(
)
i
k
k
+
1
2
k
k
+
1
k
k
+
1
Since elements with these indexes have equal weight coefficients, that on dividing
(4.13) by v , we obtain
i
=
1
i
=
1
2
k
v
+
1
ω
=
.
(4.14)
(
)
i
k
k
+
1
α some clusters occur, one of them is large
cluster with potency v and several clusters which potency is less than v ;
with that all small clusters have different potencies.
Let the largest of small clusters have potency d , and other clusters, without
limiting their generality, have potencies
1
4. With confidence level
ad , accordingly. Applying
the criteria I and II, we range elements according to their weight coefficients. We
obtain a conditional ordered series of elements
>
>
b
>
c
1
k
(or elements
k
)
Ξ
Θ
X
=
X
=
...
=
X
>
X
=
...
=
X
>
X
=
...
=
X
) >
()
( )
( )
(
)
(
)
(
)
(
1
2
v
v
+
1
v
+
d
v
+
d
+
1
v
+
d
+
a
...
...
.
>
X
=
=
X
>
X
=
=
X
(
)
(
)
(
)
( )
++
Weight coefficients of elements of each cluster are computed in the same manner
as the weight coefficients of elements of a cluster with potency v (see item 3).
We obtain
v
d
a
+
1
v
+
d
+
a
+
b
v
+
d
+
a
+
b
+
1
k
2
k
v
+
1
2
k
2
v
d
+
1
ω
=
,
i
=
1
v
;
ω
=
,
i
=
v
+
1
v
+
d
;
()
(
)
()
(
)
i
i
k
k
+
1
k
k
+
1
2
k
2
v
2
d
a
+
1
ω
=
,
i
=
v
+
d
+
1
v
+
d
+
a
;
()
(
)
i
+
1
k
k
2
k
2
v
2
d
2
a
b
+
1
ω
=
,
i
=
v
+
d
+
a
+
1
v
+
d
+
a
+
b
;
()
(
)
i
k
k
+
1
2
k
2
v
2
d
2
a
2
b
c
+
1
ω
=
,
i
=
v
+
d
+
a
+
b
+
1
k
.
()
(
)
i
k
k
+
1
5. With confidence level
α
<
1
some large clusters with identical amount of
elements occur:
a) Two clusters of identical potency v occur. Let us assume that the first
cluster consists of elements with indexes
i
=
1
v
, and the second cluster
consists of elements with indexes
. Other elements are
fractionalized into individual clusters. Let us calcu late indexes
i
=
v
+
1
2
v
ρ
ρ
or
j
j
for elements of two clusters of potency v with
j
=
1
2
v
 
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