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where the constant represents all terms in (7.15) that are independent of W
and τ ,and
E α are the expectations evaluated with respect to Z and α
respectively. This expression shows that q W,τ factorises with respect to k ,which
allows us to handle the q W,τ ( W k k )'s separately, by solving
E Z and
ln q W,τ ( W k k )=
n E Z ( z nk ln p ( y n |
W k k )) +
E α (ln p ( W k k |
α k )) + const.
(7.26)
Using the classifier model (7.7), we get
n E Z ( z nk ln p ( y n |
W k k ))
=
n E Z ( z nk )ln
w kj x n k )
j N
( y nj |
1
2 ln τ k
w kj x n ) 2 +const.
=
n
r nk
j
τ k
2 ( y nj
ln τ k + const.
= D 2
r nk
(7.27)
n
r nk y nj 2 w kj
n
τ k
2
r nk x n y nj + w kj
r nk x n x n
w kj
,
j
n
n
where r nk E Z ( z nk )isthe responsibility of classifier k for observation n ,and y nj
is the j th element of y n . The constant represents the terms that are independent
of W k and τ k .
E α (ln p ( W k k |
α k )) is expanded by the use of (7.8) and results in
E α (ln p ( W k k |
α k ))
=
j
E α ln
a τ ,b τ )
0 , ( α k τ k ) 1 I )+lnGam( τ k |
N
( w kj |
D 2
b τ τ k +const.
=
j
τ k
2 E α ( α k ) w kj w kj +( a τ
ln τ k
1) ln τ k
= D Y a τ
ln τ k
D Y + D X D Y
2
E α ( α k )
j
τ k
2
2 D Y b τ +
w kj w kj
+ const.
(7.28)
 
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