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where the constant represents all terms in (7.15) that are independent of
W
and
τ
,and
E
α
are the expectations evaluated with respect to
Z
and
α
respectively. This expression shows that
q
∗
W,τ
factorises with respect to
k
,which
allows us to handle the
q
W,τ
(
W
k
,τ
k
)'s separately, by solving
E
Z
and
ln
q
∗
W,τ
(
W
k
,τ
k
)=
n
E
Z
(
z
nk
ln
p
(
y
n
|
W
k
,τ
k
)) +
E
α
(ln
p
(
W
k
,τ
k
|
α
k
)) + const.
(7.26)
Using the classifier model (7.7), we get
n
E
Z
(
z
nk
ln
p
(
y
n
|
W
k
,τ
k
))
=
n
E
Z
(
z
nk
)ln
w
kj
x
n
,τ
−
k
)
j
N
(
y
nj
|
1
2
ln
τ
k
−
w
kj
x
n
)
2
+const.
=
n
r
nk
j
τ
k
2
(
y
nj
−
ln
τ
k
+ const.
=
D
2
r
nk
(7.27)
n
r
nk
y
nj
−
2
w
kj
n
τ
k
2
r
nk
x
n
y
nj
+
w
kj
r
nk
x
n
x
n
−
w
kj
,
j
n
n
where
r
nk
≡
E
Z
(
z
nk
)isthe
responsibility
of classifier
k
for observation
n
,and
y
nj
is the
j
th element of
y
n
. The constant represents the terms that are independent
of
W
k
and
τ
k
.
E
α
(ln
p
(
W
k
,τ
k
|
α
k
)) is expanded by the use of (7.8) and results in
E
α
(ln
p
(
W
k
,τ
k
|
α
k
))
=
j
E
α
ln
a
τ
,b
τ
)
0
,
(
α
k
τ
k
)
−
1
I
)+lnGam(
τ
k
|
N
(
w
kj
|
D
2
b
τ
τ
k
+const.
=
j
τ
k
2
E
α
(
α
k
)
w
kj
w
kj
+(
a
τ
−
ln
τ
k
−
1) ln
τ
k
−
=
D
Y
a
τ
−
ln
τ
k
D
Y
+
D
X
D
Y
2
⎛
⎞
E
α
(
α
k
)
j
τ
k
2
⎝
2
D
Y
b
τ
+
w
kj
w
kj
⎠
+ const.
−
(7.28)
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