Geology Reference
In-Depth Information
9
/
0
3
0.2
(0.2)
0.86
(20) =
2
9
/
0
3
0.3
(0.3)
1.23
(30) =
2
9
/
0
3
0.4
(0.4)
1.51
(40) =
2
9
/
0
3
0.5
(0.5)
1.69
(50) =
2
3
1
/0
3
(60) =
1
. .
0.6
0.6
1.79
2
2
3
1
3
/0
(70) =
1
.
0.7
0.7
1.88
2
2
3
1
3
(80) =
1
.
0.8
(0.8)
1.944
2
2
3
3
(90) =
1
.
0.9
(0.9)
1.99
2
(100) = 1 + 1 = 2
(110) = 1 + 1 = 2
Question 3.3
Calculate the slope of the spherical variogram near the origin. Show that
the tangent at the origin cuts the straight line
Y
=
c
at
h
= (2/3)
a
.
Answer
The tangent at the origin cuts the straight line
Y
=
c
at
h
= (2/3)
a
. The
slope of the spherical variogram near origin is obtained by differentiating
variogram function and substituting
h
= 0.
3
3
h
1
h
=
()
hc
=
2
a
2
3
a
2
dh
()
33
h
'( )
h
c
3
dh
2
a
2
a
3
c
a
(0)
Substituting
h
= 0,
which is the slope near origin.
2
3
2
c
The equation of the tangent near the origin is
Y
=
h
a
