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C
C 3
Scan order
v p
v 3
v 2
v
p
v 1
C 1
v i−1
v
i
C 2
C i+1
C i−1
C i
(a) A chain of cliques.
(b) A tree of cliques.
Fig. 7.6 Difference cases in subgraph recurrence.
C m be a chain of cliques. The two consecutive cliques C i 1
and C i share a common vertex v i 1 (2
Generally, let C 1 ,···,
i
m ). Each clique C i contains at most
three vertices, as illustrated in Figure 7.6(a).
A private vertex v i p only belongs to C i .
A head vertex v i 1 belongs to C i and C i 1 .
A tail vertex v i belongs to C i and C i + 1 .
Trivially, C 1 has no head vertex and C m has no tail vertex.
Let G i 1
= 1 j i 1 C j and G i =
S i 1
C i . To compute Pr
(
G i ,
x
v i )
, two cases
−{
}
−{
}
may arise, since C i
v i 1
and G i 1
v i 1
are conditionally independent given
v i 1 .
1. v i 1 appears. Then no other vertices in C i can appear.
2. v i 1 does not appear. In order to have x selected vertices appear in G i , we consider
two subcases.
a. no selected vertex in C i appears. Then there must be x selected vertices in G i 1
appear.
b. 1 vertex in C i appears. Then there must selected x
1 vertices in G i 1 appear.
Summarizing the above cases, we have the following theorem.
Theorem 7.4 (Conditional subgraph probabilities). Given a chain of cliques
C 1 ,···,
C m , let G i = 1 j i C j ,
C i , and v i p be the private vertex
{
v i 1 } =
C i 1
of C
i. The conditional subgraph probability of G 1 given
¬
v 1 is
v p )
1
Pr
(
Pr
(
v 1 )
,
x
=
0 ;
1
Pr
(
v 1 )
v p )
Pr
(
G 1 ,
x
v 1 )=
Pr
(
v 1 ) ,
x
=
1 ;
1
Pr
(
0
,
x
>
1 .
The conditional subgraph probability of G 1 given v 1 is
1
,
x
=
1 ;
Pr
(
G 1 ,
x
|
v 1 )=
0
,
x
=
1 .
 
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