Chemistry Reference
In-Depth Information
substitution reactions in Chapter 8, and this is why
we have purposely discussed the acidity of aromatic
derivatives in some detail.
a weak base has a large K a and thus a small p K a ,
i.e. B is favoured over BH + .
Or, put another way:
4.4
Basicity
the larger the value of p K a , the stronger is the
base;
We have already defined a base as a substance that
will accept a proton by donating a pair of electrons.
Just as we have used p K a to measure the strength of
an acid, we need a system to measure the strength of
a base. Accordingly, a basicity scale based on p K b
was developed in a similar way to p K a .
For the ionization of the base B in water
the smaller the value of p K a , the weaker is the
base.
The relationship between p K a and p K b can be
deduced as follows:
[HO ][BH + ]
[B]
K b =
K
B
H 2 O
BH
HO
+
+
[B][H 3 O + ]
[BH + ]
K a =
the equilibrium constant K is given by the formula
[B][H 3 O + ]
[BH + ]
[HO ][BH + ]
[B]
[HO ][BH + ]
[B][H 2 O]
K a × K b =
×
K
=
[H 3 O + ][HO ]
=
and since the concentration of water will be essen-
tially constant, the equilibrium constant K b and the
logarithmic p K b may be defined as
Thus, K a ×
K b reduces to the ionization constant for
water K w .
[HO ][BH + ]
[B]
K
K b =
H 2 O
H 2 O
H 3 O
+
+
HO
base
accepts
proton
acid
donates
proton
with
p K b =−
log 10 K b
This system has been almost completely dropped in
favour of using p K a throughout the acidity - basicity
scale . To measure the strength of a base, we use
the p K a of its conjugate acid, i.e. we consider the
equilibrium
In this reaction, one molecule of water is acting as
a base and accepts a proton from a second water
molecule. This second water molecule, therefore,
is acting as an acid and donates a proton. The
equilibrium constant K for this reaction is given by
the formula
K
BH
+
H 2 O
H 3 O+
B
[H 3 O + ][HO ]
[H 2 O][H 2 O]
K
=
conjugate
acid
and because the concentration of water is essentially
constant in aqueous solution, the new equilibrium
constant K w is defined as
for which
[B][H 3 O + ]
[BH + ]
K a =
[HO ][H 3 O + ]
K w =
It follows that
a strong base has a small K a and thus a large p K a ,
i.e. BH + is favoured over B;
For every hydronium ion produced, a hydroxide anion
must also be formed, so that the concentrations of
 
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