Image Processing Reference
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The analysis for the parabola y 2 = 4a o x can be carried out in an analogous
manner. Here, x i = ⌈i 2 /4a o ⌉,0 6 i 6 y n and y i = ⌊
(4a o i)⌋,0 6 i 6 n, where
the parabola is truncated by x = n. The bounds on a o can be formed as in
the case of a circle:
(y i /4i),max
i
(i 2 /4x i )) and
a l =
max(max
i
((y i + 1) 2 /4i),min
i
(i 2 /4(x i
a u =
min(min
i
−1))) and i > 1.
Clearly then, Theorem 5.2 follows.
Theorem 5.2. a l 6 a < a u if and only if D(P(a)) = D o and Domain(D o ) =
[a l ,a u ).
Example 5.3. (Fig. 5.3) Let a o = 4.3 and n = 10. So, D o X =
(0,1,1,1,1,2,3,3,4,5,6,8,9,10) and D Y = (0,4,5,7,8,9,10,10,11,12,13).
We get a l = 4.225000 and a u = 4.321429. The grid point defining a l is (10,13)
and that defining a u is (7,11).
FIGURE 5.3: Digitization of a parabola with a o = 4.3 (Example 5.3).
Reprinted from CVGIP: Graphical Models and Image Processing , 54(5)(1992), S. Chattopadhyay et al., Parameter Es-
timation and Reconstruction of Digital Conics in Normal Positions, 385-395, Copyright (1992), with permission
from Elsevier.
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