Biomedical Engineering Reference
In-Depth Information
change in rest energy, Q = M 1 + M 2 -( M 3 + M 4 ) , is negative for the endothermic
reaction. 5) The conservation of total energy requires that
(9.20)
E 1 =
E 3 + E 4 - Q ,
where E 1 , E 3 ,and E 4 are the kinetic energies of the moving particles. Conservation
of momentum gives
(9.21)
p 1 =
p 3 + p 4 ,
where p 1 , p 3 ,and p 4 are the magnitudes of the respective momenta. To calculate
the threshold energy E 1 , we eliminate either E 3 or E 4 from these two equations
and solve for the other. This procedure will give the explicit condition that E 1 must
fulfill.
We eliminate E 4 . Using the relationship, E 4 = p 4 /2 M 4 , between energy and mo-
mentum, we write with the help of Eq. (9.21)
p 4
2 M 4 =
1
2 M 4 ( p 1 - p 3 ) 2 .
(9.22)
E 4 =
Substituting p 1 =
(2 M 1 E 1 ) 1/2 and p 3 =
(2 M 3 E 3 ) 1/2 gives
1
M 4 [ M 1 E 1 -2( M 1 M 3 ) 1/2 ( E 1 E 3 ) 1/2 + M 3 E 3 ].
E 4 =
(9.23)
Using this expression in Eq. (9.20) and carrying out some algebraic manipulations,
one finds for E 3 that
E 3 - 2( M 1 M 3 E 1 ) 1/2
M 3 + M 4
E 3 - ( M 4 - M 1 ) E 1 + M 4 Q
M 3 + M 4
=
0.
(9.24)
This is a quadratic equation in E 3 , having the form
E 3 -2 A E 3 - B
(9.25)
=
0,
where A and B are the coefficients that appear in Eq. (9.24). The two roots yield
E 3 = B +2 A 2 1
A A 2 + B .
1
±
(9.26)
For E 3 to be real, A 2 + B
0:
( M 3 + M 4 ) 2 + ( M 4 - M 1 ) E 1 + M 4 Q
M 1 M 3 E 1
0,
(9.27)
M 3 + M 4
or
- Q 1+
.
M 1
M 3 + M 4 - M 1
E 1
(9.28)
energy E * above the ground-state energy,
then one must replace Q by Q - E * in this
discussion.
5 We assume that both particles are in their
ground states after the collision. If particle 3
or 4 is a nucleus in an excited state with
 
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