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a 2 c 2
K a
------
(1
a ) c
a 2 c
K a
------
(1
a )
For weak electrolytes, a is very small and may be neglected so (1
a ) is
approximately
1. The simplified expression may now be written as
K a
a 2 c
where c is the concentration, in moles per litre, and a is the degree of
ionisation of the acid. Then
( )
K a
a
c
The pH of the solution can now be determined:
[H ]
ac
Therefore,
( ) ( K a c )
K a
[H ]
c
c
Taking logarithms,
5
log K a 5
log[H ]
log c
Multiplying throughout by
1 gives
4
log K a 4
log[H ]
log c
Therefore,
5
p K a 5
pH
log c
(1.2)
Equation (1.2) applies to the ionisation of weak acids, but a similar expres-
sion can be derived for weak bases. The equation for the ionisation of a
weak base may be expressed as
B
H 2 O
3
BH
OH
(1
a ) c
ac
ac
where B is the base and BH is termed the conjugate acid of the base.
The equilibrium constant for this reaction is written as
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