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inequality is given by
2
n
2
n
σ
≤
α
n
+
1
≤
σ
σ
n
2
+
1
+
1
≤
(6.81)
−
ζ )
l
1
2
(
1
ζ
u
1
2
ζ
u
2
From inequality (6.40) it follows that
2
2
2
(
1
−
ζ )
u
3
b
⊥
γ
OLS
1
−
ζ
α
n
+
1
≤
=
(6.82)
For
ζ
→
0 (OLS), the bounds
l
1and
u
3 tend to finite values, while
u
1and
u
2 tend to infinity. It follows that
2
2
2
2
2
(
1
−
ζ )
→
b
⊥
b
⊥
α
n
+
1
≤
=
γ
OLS
(6.83)
2
From (6.81) we also derive
2
n
σ
+
1
≤
γ
OLS
(6.84)
2
For
ζ
≥
0
.
5, the following
strictest
inequalities derived from the previous
theory are true:
2
n
+
1
2
ζ
l
3
2
n
+
1
σ
σ
0
.
5
≤
ζ
≤
ζ
+
≤
α
n
+
1
≤
1
−
ζ )
u
2
2
(
(6.85)
2
n
σ
σ
n
2
ζ
+
≤
ζ
≤
1
+
1
≤
α
n
+
1
≤
ζ
l
3
2
ζ
u
3
For
ζ
→
1 (DLS) the bounds
l
3and
u
3 tend to finite values. Hence, the bound
for the DLS smallest eigenvalue is given by
2
n
σ
≤
α
n
+
1
≤
σ
n
2
+
1
(6.86)
2
which shows that the bound (2.117) is also valid for
i
=
n
+
1. In other words,
the bound (2.117) is valid for each finite eigenvalue of
K
.
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