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α
i
α
1
−
α
i
α
i
α
n
+
1
−
α
i
=
U
diag
,
...
,
0
,
...
,
i
th position
−
η
.
1
ζ
−
r
2
2
u
i
−
η
.
−
η
α
i
α
i
−
α
1
0
.
η
=
u
1
u
n
+
1
···
α
i
η
α
−
α
i
n
+
1
So the following result has been proved:
d
u
i
d
ζ
α
i
α
i
−
α
1
u
1
+···+
α
i
α
i
−
α
i
−
1
u
i
−
1
+
α
i
α
i
−
α
i
+
1
u
i
+
1
+···
=
η
α
i
−
α
n
+
1
u
n
+
1
α
i
+
1
ζ (
1
−
ζ )
α
i
α
i
−
α
j
u
j
=
(6.53)
j
=
i
Defining
τ
f
,
e
as
#
$
α
g
α
g
−
α
f
for
g
=
f
τ
f
,
g
=
(6.54)
%
0
otherwise
eq. (6.53) can be written in a more compact form as
τ
1,
i
0
.
τ
n
+
1,
i
d
u
i
d
ζ
=
η
U
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