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First Order Governing Differential Equations
The first order governing differential equations for the in-plane loaded circular disk with
axially symmetrical deformation can be obtained from the first relations of Eqs. (13.10b)
and (13.11a). The variation of th e displa ce ments and internal forces are independent of
φ
for
axially symmetric loading. Let p r (
p Vr denote the applied radial forces (force/length 2 )
in the plane of the disk, including radial pressure, centrifugal, and thermal forces, all of
which are assumed to be independent of
r
) =
φ
. Because of the symmetry,
γ r φ =
n r φ =
0
.
Also,
φ () =
0
.
From Eq. (13.8c),
φ =
u r /
r, and from Eq. (13.10b),
φ = ( ν
n r +
n
φ )/
Et or
Et
r
n
φ =
u r + ν
n r
=
= (
ν
n φ )/
= (
ν
n φ )/
=
From Eqs. (13.8c) and (13.10b),
r u r and
n r
Et ,or
r u r
n r
Et
ν Et
r
n r ]
r
r
+ ν
/
.
[ n r
From this relation and the first condition of equilibrium of
Eq. (13.11a), the first order governing equations are
u r
Et
2
du r
dr =− ν
u r
r +
1
ν
n r
(13.14a)
Et
dn r
dr =
Et
r 2
u r + ν
1
n r
p r (
r
)
r
or
u r
n r
ν/
u r
n r
0
2
d
dr
r
(
1
ν
)/
Et
=
+
(13.14b)
r 2
p r
Et
/
1
)/
r
/
=
+
dz
dr
A
z
P
Note that A is not constant as A
=
A
(
r
).
If inertia fo rc es a re included, change the ordinary
d
dr
2 u r
t 2 , where
derivatives
to partial derivatives
and replace p r by p r =− ρ∂
/∂
ρ
is the
r
mass per unit area.
In higher order form, for a disk with constant thickness and material properties,
1
r
d 2 u r
dr 2 +
2
1
r
du r
dr
1
r 2 u r =
d
dr
d
dr (
1
ν
ru r )
=−
p r
(13.14c)
Et
Integration of this relationship gives u r , which can then be placed in the first of Eqs. (13.14a)
to find n r .
The transfer and stiffness matrices from the solution of Eq. (13.14) are given in Table 13.1.
EXAMPLE 13.1 Rotating Disk
Find the displacement u r and the internal force n r of a rotating circular disk with inner and
outer radii of a and b . The angular speed of the disk is
.
Assume th at the material of the disk is homogeneous. The disk is subjected to a symmetric
loading of p r = ρ
2 , where
is the mass density (mass/area). The displacement u r and
internal force n r are independent of
r
ρ
. The governing equations for the disk are given by
Eq. (13.14), which are readily integrated. We find
φ
u r
n r
U uu
u r
n r
u r
n r
U un
r =
a +
U nu
U nn
(1)
r
=
U i
z i
z
=
z a
+
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