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or
r
φ
γ r φ
1
ν
0
n r
n
1
Et
=
ν
1 0
002
(13.10b)
φ
n r φ
(
1
+ ν)
E 1
=
s
If thermal loading effects are to be included, Eqs. (13.10a) and (13.10b), with 0
=
T 0] T , can be written as [Chapter 1, Eqs. (1.43) and (1.44)]
[
α
T
α
1
ν
0
α
E
Tt
/(
1
ν)
n r
n φ
n r φ
r
φ
γ
=
ν
10
00 1 ν
2
D
α
E
Tt
/(
1
ν)
(13.10c)
0
r
φ
E 0
s
=
E
and
1
ν
0
n r
n φ
n r φ
α
T
α
r
φ
γ
1
Et
=
+
ν
1 0
002
T
(13.10d)
(
1
+ ν)
0
r
φ
E 1
0
=
s
+
Conditions of Equilibrium
The equilibrium equations, w hich p rov id e relationships between the stress resultants and
the body forces (force/area p V =
] T , are (Fig. 13.3b)
[ p Vr
p V φ
n r
1
r
∂φ + (
n r φ
n r
n φ )
r +
+
p Vr =
0
r
n r φ =
n
(13.11a)
φ
r
1
r
∂φ +
n φ
n r φ
2 n r φ
r
+
+
p V φ =
0
r
or in matrix form,
p Vr
p V φ
n r
n φ
n r φ
+
1
/
r
1
/
r
(
1
/
r
)∂ φ
r
+
=
0
0
(
1
/
r
)∂ φ
+
2
/
r
(13.11b)
r
D s
+
=
s
p V
0
Boundary Conditions
The displacement boundary conditions are
u r =
u r
on S u
(13.12)
u
φ =
u
φ
and the force boundary conditions are
p r
=
p r
on S p
(13.13)
p φ =
p
φ
where p r and p
are the surface forces (force/length) in the r and
φ
directions around the
φ
circumference of the disk.
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