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or
r
φ
γ
r
φ
1
−
ν
0
n
r
n
1
Et
=
−
ν
1 0
002
(13.10b)
φ
n
r
φ
(
1
+
ν)
E
−
1
=
s
If thermal loading effects are to be included, Eqs. (13.10a) and (13.10b), with
0
=
T
0]
T
, can be written as [Chapter 1, Eqs. (1.43) and (1.44)]
[
α
T
α
1
ν
0
α
E
Tt
/(
1
−
ν)
n
r
n
φ
n
r
φ
r
φ
γ
=
−
ν
10
00
1
−
ν
2
D
α
E
Tt
/(
1
−
ν)
(13.10c)
0
r
φ
E
0
s
=
E
−
and
1
−
ν
0
n
r
n
φ
n
r
φ
α
T
α
r
φ
γ
1
Et
=
+
−
ν
1 0
002
T
(13.10d)
(
1
+
ν)
0
r
φ
E
−
1
0
=
s
+
Conditions of Equilibrium
The equilibrium equations,
w
hich
p
rov
id
e relationships between the stress resultants and
the body forces (force/area
p
V
=
]
T
, are (Fig. 13.3b)
[
p
Vr
p
V
φ
∂
n
r
∂
1
r
∂
∂φ
+
(
n
r
φ
n
r
−
n
φ
)
r
+
+
p
Vr
=
0
r
n
r
φ
=
n
(13.11a)
φ
r
1
r
∂
∂φ
+
∂
n
φ
n
r
φ
∂
2
n
r
φ
r
+
+
p
V
φ
=
0
r
or in matrix form,
∂
p
Vr
p
V
φ
n
r
n
φ
n
r
φ
+
1
/
r
−
1
/
r
(
1
/
r
)∂
φ
r
+
=
0
0
(
1
/
r
)∂
φ
∂
+
2
/
r
(13.11b)
r
D
s
+
=
s
p
V
0
Boundary Conditions
The displacement boundary conditions are
u
r
=
u
r
on
S
u
(13.12)
u
φ
=
u
φ
and the force boundary conditions are
p
r
=
p
r
on
S
p
(13.13)
p
φ
=
p
φ
where
p
r
and
p
are the surface forces (force/length) in the
r
and
φ
directions around the
φ
circumference of the disk.
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