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be constant over the width b , the axial equilibrium requirements are
τ
bdx
=
dF or
σ
1
b
dF
dx =
1
b
d
x
dx
τ =
dA
(12.40)
A 0
= A 0 σ x dA . Substitution of
where F
σ x from Eq. (12.39) into Eq. (12.40) yields
A 0
) dA
M y I yy
+ M z I yz
I yy I zz
M y I yz
+ M z I zz
I yy I zz
1
b
A N
I z
I y
τ =
+
E
T
(12.41)
I yz
I yz
A 0
= A 0 dA, I z = A 0 z dA, I y = A 0 ydA .
The conditions of equilibrium relating the bending moments to the shear forces can be
expressed as [Chapter 1, Eq. (1.113)]
() =
where
d
/
dx, A 0
dM Ty
dx
M y =
= V z ,
V z
+
V Tz
with
V Tz
=
(12.42)
dM Tz
dx
M z =−
V Ty =− V y ,
V y
with
V Ty =
Equation (12.41) then can be written as
A 0
) dA
V z I yy
V y I yz
I yy I zz
V z I yz
V y I zz
I yy I zz
1
b
A N
I z
I y
τ =
+
E
T
(12.43)
I yz
I yz
A 0
or
A 0
) dA
I y I zz
I z I yz
I z I yy
I y I yz
1
b
A N
I yz V y
I yz V z
τ =
+
+
E
T
I yy I zz
I yy I zz
A 0
These expressions should be regarded as reasonable approximations, since the assump-
tion that
is constant over the width is often not valid. More accurate shear stresses can be
calculated using a finite element implementation of theory of elasticity, as discussed later.
τ
Shear Stress Due to Torsional Moment
For solid cross-sections, the shear stresses due to torsion are those resulting from M tP
(Eq. 12.9). These shear stresses are given in Chapter 1, Eq. (1.143). In calculating these
stresses, the warping of the cross-section must be considered. The longitudinal displace-
ment in the x direction due to warping is [Eq. (12.5c)]
u x
= ω(
y, z
(12.44a)
ψ =− φ . Also, if the displacements due to bending are not
From Wagner's hypothesis,
considered [Eq. (12.6)],
u y
=− φ
z,
u z
= φ
y
(12.44b)
Then
G
φ ∂ω
z
y +
u x
u y
τ
=
G
γ
=
=−
G
y +
(12.45a)
xy
xy
x
G
φ ∂ω
y
u x
z +
u z
τ xz =
G
γ xz =
=−
G
z
(12.45b)
x
which are in agreement with Chapter 1, Eqs. (1.142) and (1.143).
Although formulas for the warping function
ω
are available [Pilkey, 1994] for a few cross-
ω
sectional shapes,
can be computed for arbitrary shapes as discussed in Section 12.2.2.
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