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FIGURE 11.4
Stability and instability from the standpoint of energy.
Suppose the particular variation that corresponds to the critical load is
δ
. Then
1
2
δ
1
2
δ
δ
˚
2
˚
2
˚
δ()
=
δ
+
+···
=
δ
=
0
(11.5)
or
1
2
δ
2
˚
δ()
=
δ
=
0
(11.6)
Equation (11.6) can be used as the criterion for computing the critical load. It holds only for
conservative loading.
EXAMPLE 11.2 A Simple Example
Return to t
he
weightless, rigid rod with the elastic base attachment of Fig. 11.2. The potential
energy for
H
=
0 is given by
=
(strain energy of the spring)
−
(potential energy of the applied loading)
1
2
k
2
=
φ
−
PL
(
1
−
cos
φ)
(1)
˚
For equilibrium
δ
=
0or
k
φ
−
PL
sin
φ
=
0
(2)
which corresponds to the value of
P
of Eq. (3) of Example 11.1.
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