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The numerical determination of Ritz vectors takes less computational work than needed
to calculate mode shapes. This reduces the numerical effort needed in time-domain solu-
tions of complex structural problems. In addition, the method possesses the advantages
of static condensation, Guyan reduction, and higher mode truncation [Wilson, 1985]. The
examples studied in Wilson, et al. (1982) have shown that a dynamic analysis based on Ritz
vectors gives more accurate results, with fewer vectors, than when the usual mode shapes
are employed.
Suppose the applied force
P
in the governing equations of Eq. (10.97) can be expressed
as a product of a vector of spatial distributions of loading and a function of time. That is,
C V
M V
+
+
KV
=
P
=
F
(
s
)
g
(
t
)
(10.130)
The time-independent vector
F
(
s
)
represents the spatial distribution of the external force
and
g
is a function of time only. Equation (10.130) is reduced in size by using a set of
global Ritz vectors
x
1
,
x
2
,
(
t
)
...
.
×
n
matrix whose
i
th column is
x
i
. The displacement vector
V
is written in terms of the Ritz
vectors as
,
x
n
Let the number of entries of
V
be
n
d
and let
X
be the
n
d
V
=
Xy
(10.131)
where
y
is a vector with
n
elements. When Eq. (10.131) is substituted into Eq. (10.130) and
the results premultiplied by
X
T
, the following set of differential equations is obtained
M
1
y
+
C
1
y
˙
+
K
1
y
=
F
1
g
(
t
)
(10.132)
The number of scalar differential equations in Eq. (10.132) is equal to
n
, the number of Ritz
vectors chosen in the expansion of Eq. (10.131). In Eq. (10.132)
X
T
MX
M
1
=
(10.133)
X
T
KX
=
K
1
(10.134)
X
T
CX
C
1
=
(10.135)
X
T
F
F
1
=
(10.136)
The condensed relationship of Eq. (10.132) can be solved by one of the direct step-by-step
integration methods discussed in Section 10.5. To complete the derivation of Eq. (10.132),
Ritz vectors will now be explicitly defined. The first Ritz vector
x
1
is taken as the displace-
ment vector obtained from a static analysis with
F
(
s
)
as the external force and is found by
solving the linear algebraic equation
Kx
1
=
F
(
s
)
(10.137)
for
x
1
. The Ritz vector
x
1
, which is the first column of the matrix
X
, is found from
x
1
by
normalizing
x
1
with respect to the mass matrix
M
x
1
x
1
=
x
∗
T
1
(10.138)
Mx
1
The normalized vector
x
1
has the property
x
1
Mx
1
=
1
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