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FIGURE 9.8
A hollow cylinder with internal pressure.
kept below prescribed values. These conditions can then be added to the constraint condi-
tions of the minimax formulation.
EXAMPLE 9.5 Boundary Element Solution for a Thick Cylinder under Internal Pressure
C
ompute the displacements of the thick cylinder of Fig. 9.8 under an internal pressure of
p
1 GN/m
2
200 GN/m
2
, and Poisson's
=
0
.
.
The modulus of elasticity of the material is
E
=
ratio is 0.25.
This problem can be treated as a plane strain problem (Section 1.3.1). The displacements
on a point
ξ
inside the body or on the boundary are expressed as [Eq. (9.88)]
u
j
p
ij
dS
p
j
u
ij
dS
p
Vj
u
ij
dA
c
i
u
i
(ξ )
+
=
+
(1)
S
S
A
or
p
∗
u
dS
u
∗
p
dS
u
∗
p
V
dA
cu
(ξ )
+
=
+
(2)
S
S
A
The terms
u
ij
and
p
ij
are given in Eq. (9.74) and (9.78). The displacement form of the governing differential
equation is [Eq. (9.53)]
where
A
is the area of the cross-section of the cylinder, and
i, j
=
1
,
2
.
1
p
Vi
G
2
u
i
+
∇
u
k,ki
+
=
0
i, k
=
1
,
2
(3)
1
−
2
ν
Express the displacement in terms of the Galerkin vector [Eq. (9.58)]
1
u
i
=
g
i,kk
−
g
k,ik
i, k
=
1
,
2
(4)
2
(
1
−
ν)
where
g
i
is the component of the Galerkin vector. Substitute (4) into (3) to obtain
p
Vi
G
4
g
i
+
∇
=
0
(5)
Let
p
Vi
=
δ(ξ
,x
)
a
i
(6)
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