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FIGURE 9.8
A hollow cylinder with internal pressure.
kept below prescribed values. These conditions can then be added to the constraint condi-
tions of the minimax formulation.
EXAMPLE 9.5 Boundary Element Solution for a Thick Cylinder under Internal Pressure
C ompute the displacements of the thick cylinder of Fig. 9.8 under an internal pressure of
p
1 GN/m 2
200 GN/m 2 , and Poisson's
=
0
.
.
The modulus of elasticity of the material is E
=
ratio is 0.25.
This problem can be treated as a plane strain problem (Section 1.3.1). The displacements
on a point
ξ
inside the body or on the boundary are expressed as [Eq. (9.88)]
u j p ij dS
p j u ij dS
p Vj u ij dA
c i u i (ξ ) +
=
+
(1)
S
S
A
or
p u dS
u p dS
u p V dA
cu
(ξ ) +
=
+
(2)
S
S
A
The terms u ij and
p ij are given in Eq. (9.74) and (9.78). The displacement form of the governing differential
equation is [Eq. (9.53)]
where A is the area of the cross-section of the cylinder, and i, j
=
1 , 2
.
1
p Vi
G
2 u i +
u k,ki +
=
0
i, k
=
1 , 2
(3)
1
2
ν
Express the displacement in terms of the Galerkin vector [Eq. (9.58)]
1
u i =
g i,kk
g k,ik
i, k
=
1 , 2
(4)
2
(
1
ν)
where g i is the component of the Galerkin vector. Substitute (4) into (3) to obtain
p Vi
G
4 g i +
=
0
(5)
Let
p Vi = δ(ξ
,x
)
a i
(6)
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