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For each node j, the element matrices H ij and G ij are assembled to form the global matri-
ces H j and G j such that
M
H j =
1 H ij
[ H j 1 H j 2 ··· H jj ··· H jN ]
=
i
=
(9.35)
M
G j
1 G ij
[ G j 1 G j 2
··· G jj
··· G jN ]
=
=
i
=
The summation process is similar to that given in Chapter 5 for the stiffness matrices, i.e.,
the entries in H ij or G ij corresponding to a common node are added to form an entry in
H j or G j for the node. Since the second term on the left-hand side and the first term on the
right-hand side of Eq. (9.34) involve all the nodal values of u and q, H j and G j are of the
order of 1
N, where N is the total number of nodes. Introduce global vectors containing
nodal values of u and q, V
×
v 1 v 2 ··· v j ··· v N ] T , P
q N ] T . The assembly
=
[
=
[ q 1 q 2 ···
q j ···
process results in a linear equation for node j
v j + H j V
= G j P
c
+
B j
Here, c can be replaced by c j because the value of c depends on the smoothness of the
boundary at node j . Put these equations together according to the global node order for all
N nodes to form the global equation
+ HV
= GP
CV
+
B
(9.36)
where
H 1
H 2
.
H j
·
H N
G 1
G 2
.
G j
·
G N
B 1
B 2
.
B j
·
B N
H
G
=
,
=
,
and
B
=
Matrices H and G are of order N
×
N and B is a vector of order N
×
1
.
Matrix C
=
diag
(
cc
···
c
)
+ H and G
= G so that this equation becomes
is an N
×
N diagonal matrix. Let H
=
C
=
+
HV
GP
B
(9.37)
Note that the diagonal elements of H involve the constant c, which is equal to
απ
in
Eq. (9.29) when
ξ
is on a smooth boundary and equal to another value when the boundary
at
is not smooth. The constant c is often cumbersome to handle. A strategy to circumvent
the treatment of this constant is to avoid the explicit evaluation of the diagonal elements of H .
Examine Eq. (9.37) in some detail. It can be seen that matrices H and G depend on the
fundamental solution, the shape functions, and the contour of the boundary. They do not
depend on V , P , and B . The diagonal entries H ii of H , which involve the cumbersome
c , can be determined by assigning judiciously chosen values to V , P , and B in Eq. (9.36).
Suppose we have V
ξ
I , which is a vector with unit entries. When the variable V is unity
over the whole region, its derivatives are zero. Thus, P , which contains nodal values of q,
is zero. Also set b
=
=
0 , leading to B
=
0
.
Substitute these assumptions into Eq. (9.37) to
obtain
=
HI
0
(9.38)
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