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For each node
j,
the element matrices
H
ij
and
G
ij
are assembled to form the global matri-
ces
H
j
and
G
j
such that
M
H
j
=
1
H
ij
[
H
j
1
H
j
2
···
H
jj
···
H
jN
]
=
i
=
(9.35)
M
G
j
1
G
ij
[
G
j
1
G
j
2
···
G
jj
···
G
jN
]
=
=
i
=
The summation process is similar to that given in Chapter 5 for the stiffness matrices, i.e.,
the entries in
H
ij
or
G
ij
corresponding to a common node are added to form an entry in
H
j
or
G
j
for the node. Since the second term on the left-hand side and the first term on the
right-hand side of Eq. (9.34) involve all the nodal values of
u
and
q,
H
j
and
G
j
are of the
order of 1
N,
where
N
is the total number of nodes. Introduce global vectors containing
nodal values of
u
and
q,
V
×
v
1
v
2
···
v
j
···
v
N
]
T
,
P
q
N
]
T
. The assembly
=
[
=
[
q
1
q
2
···
q
j
···
process results in a linear equation for node
j
v
j
+
H
j
V
=
G
j
P
c
+
B
j
Here,
c
can be replaced by
c
j
because the value of
c
depends on the smoothness of the
boundary at node
j
. Put these equations together according to the global node order for all
N
nodes to form the global equation
+
HV
=
GP
CV
+
B
(9.36)
where
H
1
H
2
.
H
j
·
H
N
G
1
G
2
.
G
j
·
G
N
B
1
B
2
.
B
j
·
B
N
H
G
=
,
=
,
and
B
=
Matrices
H
and
G
are of order
N
×
N
and
B
is a vector of order
N
×
1
.
Matrix
C
=
diag
(
cc
···
c
)
+
H
and
G
=
G
so that this equation becomes
is an
N
×
N
diagonal matrix. Let
H
=
C
=
+
HV
GP
B
(9.37)
Note that the diagonal elements of
H
involve the constant
c,
which is equal to
απ
in
Eq. (9.29) when
ξ
is on a smooth boundary and equal to another value when the boundary
at
is not smooth. The constant
c
is often cumbersome to handle. A strategy to circumvent
the treatment of this constant is to avoid the explicit evaluation of the diagonal elements of
H
.
Examine Eq. (9.37) in some detail. It can be seen that matrices
H
and
G
depend on the
fundamental solution, the shape functions, and the contour of the boundary. They do not
depend on
V
,
P
, and
B
. The diagonal entries
H
ii
of
H
, which involve the cumbersome
c
, can be determined by assigning judiciously chosen values to
V
,
P
, and
B
in Eq. (9.36).
Suppose we have
V
ξ
I
,
which is a vector with unit entries. When the variable
V
is unity
over the whole region, its derivatives are zero. Thus,
P
, which contains nodal values of
q,
is zero. Also set
b
=
=
0
,
leading to
B
=
0
.
Substitute these assumptions into Eq. (9.37) to
obtain
=
HI
0
(9.38)
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