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Thus, the unknowns
u are obtained by solving
k u
u
=
p u
(7.58)
i
v
N u
In the case of a uniform beam, R
= (
EI
w
)
p z and
w =
w , so that Galerkin's relations
would be
L
L
EI N i u )
N u (
N u
dx
w
p z dx
=
0
0
0
(7.59a)
=
k u
w
p u
0
or
k u
w
=
p u
(7.59b)
Remember that it is necessary that the basis functions N u satisfy all of the boundary condi-
tions. They must also be sufficiently differentiable.
Galerkin's method can also be viewed from the standpoint of a variational technique.
R ecall from Chapter 1 or 2 that the solid continuum relations of Eq. (7.5a), D T E Du
+
D T ED
p V =
0 , is an equilibrium expression. Thus, the residual (Eq. 7.56) R
=
u
+
p V
is
an “out-of-balance” force. A reasonable variational integral would seem to be
u T R dV
V δ
=
0
(7.60)
since this is of the form of work. Thus,
u T
D T ED
V δ
(
u
+
p V )
dV
=
0
(7.61)
N u
With
u
=
u , Eq. (7.61) becomes
u T N u (
D T ED N u
V δ
+
p V )
=
u
dV
0
(7.62a)
or
u T
dV
dV
δ
N u (
D T ED N u )
N u p V
u
+
=
0
(7.62b)
V
V
k u
p u
so that
u can be obtained from the familiar linear relationship
k u
u
=
p u
(7.63)
These are the same expressions given in Eq. (7.57), which were based on Galerkin's
weighted residual method.
Galerkin's relations of Eq. (7.59) for a uniform beam are readily derived from a variational
integral. Begin with
L
0 (
i
v
EI
w
p z )δw
dx
=
0
(7.64)
which, with
w =
N u
w , becomes
w T L
0
N u EI N i u dx
N u p z dx
L
δ
w
=
0
(7.65a)
0
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