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Then calculate the elements of the Jacobian matrix, using the shape functions of Eq.
(6.131),
4
x
∂ξ =
N i
∂ξ
1
4 [
x i =
x 1 (
1
η) +
x 2 (
1
η) +
x 3 (
1
+ η)
x 4 (
1
+ η)
]
i
=
1
4
x
∂η =
N i
∂η
1
4 [
x i
=
x 1
(
1
ξ)
x 2
(
1
+ ξ) +
x 3
(
1
+ ξ) +
x 4
(
1
ξ)
]
i
=
1
(1)
4
y
∂ξ =
N i
∂ξ
1
4 [
y i
=
y 1
(
1
η) +
y 2
(
1
η) +
y 3
(
1
+ η)
y 4
(
1
+ η)
]
i
=
1
4
y
∂η =
N i
∂η
1
4 [
y i
=
y 1
(
1
ξ)
y 2
(
1
+ ξ) +
y 3
(
1
+ ξ) +
y 4
(
1
ξ)
]
i
=
1
For element
e ,x 1 =
x 4 =
2 ,x 2 =
3 ,x 3 =
5 ,y 1 =
0 ,y 2 =
2 ,y 3 =
y 4 =
3
=
+ 2
1
η
2
1
3
4 (
det J
=
1
+ η ξ)
(2)
1
+ ξ
2
2
1
The determinant J is not non-zero everywhere. Along
, det J is zero, and the Jaco-
bian matrix is singular. This means that the coordinate transformation cannot be inverted
somewhere in the element, and implies that for this element an interior angle greater than
π
ξ =
1
+ η
should be avoided.
A more general investigation of the effect of certain interior angles can be conducted
from the standpoint of det J . Because the evaluation of the stiffness matrix involves dA ,
consider a small parallelogram area at a vertex of an element. This small area uses the two
boundaries of the element as its sides (see Fig. 6.44b). Let the length of these two sides be
dr 1 and dr 2 . Then
dA
=
dr 1
·
dr 2
·
sin
θ
(3)
Since (Eq. 6.137) dA
=
det J d
ξ
d
, it follows that
det J
η
=
dr 1
·
dr 2
·
sin
θ/(
d
ξ
d
η)
(4)
is small or close to 180 , det J will be very small. Also, if
It is apparent that if
is larger
than 180 , det J becomes negative. In general, an interior angle should not be too small or
too large. Thus, it is often recommended that interior angles less than 30
θ
θ
or greater than
150 be avoided.
6.7.3 Instabilities
Instabilities or spurious singular modes in the elements occur due to deficiencies in the for-
mulation of the elements. These instabilities are numerical phenomena, not related to the
buckling treated in Chapter 11, which are discussed in numerous references on finite ele-
ments such as Cook, et al. (1989). Particular instability characteristics, which often entail
rank deficiencies , are referred to by such names as zero-energy modes, hourglass modes, kinematic
modes , and mechanisms .
To gain some insight into this problem, consider a zero-energy mode, which by definition
corresponds to a displacement field that does not represent rigid body motion, yet produces
zero strain energy. A stiffness matrix constructed by numerical integration is based on values
obtained at the integration points of the quadrature rule. If a low order quadrature rule
(few integration points) is employed and the strains happen to be zero at the integration
points, a zero-energy mode occurs, leading to a stiffness matrix that is equal to zero.
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