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Answer:
U
Xb
10
−
5
10
−
5
10
−
1
=−
7
.
491909
×
in.,
U
Zb
=
7
.
491909
×
in.,
=
1
.
254046
×
b
Global Nodal Forces
Element 1
Element 2
P
Xa
P
Za
M
a
P
Xb
P
Zb
M
b
−
749
.
78
P
Xb
P
Zb
M
b
P
Xc
P
Zc
M
c
−
749
.
78
−
.
−
.
749
78
749
78
249
.
78
500
.
00
=
=
749
.
78
749
.
78
749
.
78
749
.
78
500
.
00
249
.
78
Local Element Forces
Element 1
Element 2
N
a
V
a
M
a
N
b
V
b
M
b
N
b
V
b
M
b
N
c
V
c
M
c
749
.
78
−
749
.
78
−
749
.
78
−
749
.
78
249
.
78
500
.
00
=
=
−
749
.
78
749
.
78
749
.
78
749
.
78
500
.
00
249
.
78
5.46 Find the displacements at the nodes of the frame of Fig. P5.46.
FIGURE P5.46
Frame.
Answer:
Yc
]
T
V
=
[
U
Xb
U
Zb
θ
U
Xc
U
Zc
θ
Yb
00554]
T
=
[0
.
01146
0
.
01924
−
0
.
00820
0
.
00790
0
.
03459
0
.
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