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FIGURE 5.32
Equilibrium states b 0 for the loading.
column of b 0 is found in a similar fashion. These equilibrium states for the loads result in
0
0
1
/
31
/
3
2
/
3
1
/
3
b 0 =
(7)
1
/
32
/
3
1
/
31
/
3
0
0
where the first and second colu m ns correspond to nod es b
(
M b )
and c
(
M c )
, respectively.
Matrix b 1 is found by setting P equal to zero in p
=
b 0 P
+
b 1 P x and using R b =
1 ,R c =
0,
followed by R b =
Apply a summation of moments for obtaining equilibrium of
the configurations of Fig. 5.33. The resulting moments
0 ,R c =
1
.
(
p
)
at the end of the bar form the first
column of b 1 .
The second column of b 1 is determined similarly. These calculations lead to
0
0
2
/
3
/
3
2
/
3
/
3
b 1 =
(8)
/
3
2
/
3
/
3
2
/
3
0
0
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