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to zero except for the element corresponding to the column being calculated. This entry
should be set equal to one. Then this column of b 0 is equal to p
T h us, to set up b 0 , a unit
value is employed one at a time for each of the applied loads of P , while the redundant
forces P x are set equal to zero. The forces p (which are now equal to a column of b 0 ) can then
be computed using equilibrium alone, since the structure under this loading is statically
determinate.
Matrix b 1 can be computed in a similar manner. This time, set the applied loads P equal
to zero, and give the redundants P x unit values one by one. Those redundants not assuming
a unit value are set to zero. This leads to the equilibrium states b 1
.
=
p , column by column.
In theory, this procedure for determining b 0 and b 1 applies to any problem. In practice,
however, it is often difficult to establish b 0 and b 1 because it is not easy to determine the
equilibrium states automatically.
Insertion of the equilibrium conditions p
bP in the form of Eq. (5.125) into the principle
of complementary virtual work expression will provide equations in terms of the system
nodal forces. Thus,
=
M
p iT
v i
v i
p T
p T
1 δ
(
) = δ
(
v
v
) = δ
(
fp
v
)
i
=
P x b 1 [ f
= δ
(
b 0 P
+
b 1 P x )
v ]
=
0
(5.126)
where
δ
p
= δ
p 0 + δ
p x = δ
p x =
b 1 δ
P x
f 1
=
f 2
diagonal [ f i ] is an unassembled
global flexibility matrix
f
=
. . .
f M
=
[ v 1
v 2
...
v M ] T
.
v , v are unassembled displacement vectors, e.g., v
Define
b 1 fb 1
F
=
(5.127)
as the assembled system flexibility matrix and
b 1 (
=−
)
V
fb 0 P
v
(5.128)
as the assembled applied displacement vector, so that Eq. (5.126) becomes
P x (
δ
FP x
V
) =
0
or
=
FP x
V
(5.129)
which is a set of algebraic equations for the un kn own nodal forces. These equations repre-
sent the global statement of compatibility V
V for a ll node s of the system.
If there are no non-ze ro prescribed displacements v , i.e., v
=
=
0, then from Eqs. (5.128)
and (5.129) with P x
=
X P , the nodal force equations become
V
=
FX
(5.130)
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