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Thus, by setting
δ
P k
=
1 , Eq. (3.15) takes the form
L
M
EI δ
w k =
Mdx
(3.17)
0
Similar relations apply for the effects of axial extension and shear deformation. In using Eq.
(3.17), remember that the moment M is due to the actual loads on the structure, whereas
the moment
δ
δ
M is due to the virtual (unit) load. If the slope at location k is desired,
M in
Eq. (3.17) should be due to a virtual (unit) moment at k .
EXAMPLE 3.12 Statically Determinate Beam
Use the unit load method to find the vertical deflection at the free end of a cantilevered beam
carrying a distributed load p 0 (Fig. 3.10a). Show how this solution should be extended to
encompass the beam of Fig. 3.10c with a sudden jump in cross-section. Also, find the slope
at the free end.
Apply a virtual (unit) force at the point where the deflection is sought (Fig. 3.10b). From
the equilibrium condition, the moment
Similarly,
the summation of moments for a segment with the actual loading p 0 (Fig. 3.10a) gives
M
δ
M generated by this force is
δ
M
=−
x
.
p 0 x 2
=−
/
2
.
We find
L
L
L
0 =
p 0 x 2
p 0 x 4
8 EI
p 0 L 4
8 EI
δ
MM
EI
x
(
/
2
)
w
=
dx
=
dx
=
(1)
0
EI
0
0
as the deflection at the free end.
In utilizing the unit load method, both the real and the virtual internal forces were chosen
to satisfy equilibrium.
Extend this solution to a beam of piecewise constant varying cross-section by computing
the internal complementary virtual work for each segment of the beam separately and
FIGURE 3.10
Cantilevered beam for unit load method examples.
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