Agriculture Reference
In-Depth Information
Hardy-Weinberg Equilibrium Part 2
If we mate two individuals that are heterozygous (e.g., Bb) for
a trait what will we find? (Let's make the Punnett square).
Look at that. In this group our resulting offspring will be:
1 BB,
2 Bb,
1 bb
This means that:
25% of their offspring are homozygous for the dominant allele (BB).
50% are heterozygous like their parents (Bb) and
25% are homozygous for the recessive allele (bb).
Now look at this closely. Unlike their parents Bb Bb, 25%
will express the recessive phenotype bb. So if we where given two
parents that displayed golden bud but where BOTH heterozygous for
that trait Bb, we would also produce offspring that have silver bud. But
since Bb is dominant in both parents, neither of the parents would
display the phenotype for silver bud.
This is really what breeding is all about. When we have a
strain that we want to keep, how do we know that the parts we want to
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