Environmental Engineering Reference
In-Depth Information
Example 10.4
Problem: What is the sludge pumped in pounds per day?
Solution :
Sludge = 43,200 gal/day × 8.34 lb/gal = 360,300 lb/day
10.4.5 Pounds solids Pumped per day
Solids Pumped (lb/day) = Sludge Pumped (gpd) × % Solids
(10.5)
Example 10.5
Problem: What are the solids pumped in pounds per day?
Solution:
Solids Pumped = 360,300 lb/day × 0.0370 = 13,331 lb/day
10.4.6 Pounds volatile Matter Pumped per day
Volatile Matter (lb/day) = Solids Pumped (lb/day) × %VM
(10.6)
Example 10.6
Problem: What is the volatile matter pumped in pounds per day?
Solution:
Volatile Matter = 13,331 lb/day × 0.66 = 8798 lb/day
Note: If you wish to calculate the pounds of solids or the pounds of
volatile solids removed per day, the individual equations demonstrated
above can be combined into a single calculation:
Solids (lb/day)
=
PumpTime(min/cycle)
×
Frequ
ency (cycles/day)
(10.7a)
×
Rate (gpm)8.34lb/gal
×
× olids
S
Volatile Matter(lb/day)
=
Time (min/cycle)
× requency (cycles/day)
Rate (gpm)8.34lb/g
F
(10.7b)
×
×
al
×
% Solids%VM
×
Example 10.7
Solids
=
15 min/cycle24 cycles/day120 gpm8
×
×
× .34lb/gal
×
0.0370
=
=
13,331lb/day
VM
15 min/c
ycle24 cycles/day120 gpm8.34lb/gal
×
×
×
× 370 66
0.0
×
=
8798lb/day
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