Environmental Engineering Reference
In-Depth Information
Note:
Use the following information for Example 10.2 through Example
10.7:
Operating time = 15 min/cycle
Frequency = 24 cycles/day
Pump rate = 120 gpm
Solids = 3.70%
Volatile matter = 66%
10.4.2 sludge Pumping Time
The sludge pumping time is the total time (in minutes) that the
pump operates during a 24-hr period.
Pump Operating Time = Time/Cycle (min)
(10.2)
× Frequency (cycles/day)
Example 10.2
Problem:
Using the data given above, what is the pump operating time?
Solution:
Pump Operating Time = 15 min/hr × 24 cycles/day = 360 min/day
10.4.3 gallons sludge Pumped per day
Sludge (gpd) = Operating Time (min/day)
(10.3)
× Pump Rate (gpm)
Example 10.3
Problem:
What is the sludge pumped in gallons per day?
Solution:
Sludge = 360 min/day × 120 gpm = 43,200 gpd
10.4.4 Pounds sludge Pumped per day
Sludge (lb/day) = Sludge Pumped (gal) × 8.34 lb/gal
(10.4)
