Civil Engineering Reference
In-Depth Information
In the present case, the twist angle from the simplified ( 2.91 ) is precise enough.
The maximum stresses on both of the rope ends can then be calculated with the
twist angles from ( 2.91a ) and ( 2.91b ).
By analysing the equations, it will be found that the stresses are independent
from the rope diameter and depend only on:
• The constants involved (Tables 1.8 , 1.9 and 2.6 ) the rope construction being
considered
• The wire rope length L and
• The specific tensile force S 0 /d 2
on the lower rope end.
Example 2.14b Wire stresses caused by twisting the rope
Wire ropes supported non-rotated at both ends, continuation of Example 2.11.
The data of Example 2.11 is again valid. Further data of the Warrington rope being
considered has been taken from Tables 1.8 , 1.9 and 2.6 . The rope lay angles are
a ¼ a 3 ; 1 ¼ 15
b ¼ b 1 ¼ 20 :
and
Data:
rope construction
Warrington FC
number of strands
8
lay direction
sZ
rope diameter
d = 16 mm
rope length
L = 500 m
tensile force, lower rope end
S = 10 kN
twist angle, lower rope end
x = 178/100d
tensile force, upper rope end
S = 14,35 kN
twist angle, upper rope end
x = -164/100d
Results: for the lower rope end
Wire layer
0
1
2
3
Torsional stress s
-51
-60
-61
-46
Longitudinal stress from rope twist r rot
101
55
-38
-60
Longitudinal stress from the rope force r S
137
135
132
131
Resulting longitudinal wire stress r res
238
191
94
71
Results: for the upper rope end
Wire layer
0
1
2
3
Torsional stress s
57
55
56
42
Longitudinal stress from rope twist r rot
-94
-52
35
56
Longitudinal stress from the rope force r S
197
194
189
188
Resulting longitudinal wire stress r res
103
143
224
244
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