Civil Engineering Reference
In-Depth Information
Example 2.5: Frequency of a mass hanging on a wire rope
Data:
Filler 6 9 19-IWRC-sZ (ten times loaded)
Mass M = 1,000 kg
Rope diameter d = 10 mm
Rope length L = 50 m
Results:
With
A = C 2 d 2 = 45.7 mm 2
the
wire
rope-cross
section
with
C 2 = 0.457
accordingly Table 1.9 , the rope tensile stress is
r m ¼ M g
A
¼ M g
C 2 d 2 ¼ 1 ; 000 9 : 81
0 : 457 10 2 ¼ 218 N/mm 2 :
According to ( 2.50 ) and ( 2.52 ), the wire rope elasticity module is
E S ¼ 119,300 N = mm 2 :
From that, according to ( 2.58 ), the spring constant is
c S ¼ 119 ; 300 44 : 9
50
¼ 107,130 N/m
and the frequency according to ( 2.57 )is
r
107,130
1,000
1
2 p
f 0 ¼
¼ 1 : 6511 = s :
2.2.4.3 Transverse Waves
A short-time local (lateral) deflection moves as a wave along the wire rope. Czitary
( 1931 ) investigated these waves theoretically and he pointed out that the tensile
force of a wire rope can be calculated by measuring the wave running time.
According to Zweifel ( 1961 ) the velocity of a transverse wave is
s
g S
q
½1 þ EI
S
ð 2 p
k
Þ 2
t ¼
:
ð 2 : 61 Þ
In this S is the rope tensile force in N;
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