Civil Engineering Reference
In-Depth Information
Example 2.5: Frequency of a mass hanging on a wire rope
Data:
Filler 6 9 19-IWRC-sZ (ten times loaded)
Mass M = 1,000 kg
Rope diameter d = 10 mm
Rope length L = 50 m
Results:
With
A = C
2
d
2
= 45.7 mm
2
the
wire
rope-cross
section
with
C
2
= 0.457
accordingly Table
1.9
, the rope tensile stress is
r
m
¼
M
g
A
¼
M
g
C
2
d
2
¼
1
;
000
9
:
81
0
:
457
10
2
¼ 218 N/mm
2
:
According to (
2.50
) and (
2.52
), the wire rope elasticity module is
E
S
¼ 119,300 N
=
mm
2
:
From that, according to (
2.58
), the spring constant is
c
S
¼
119
;
300
44
:
9
50
¼ 107,130 N/m
and the frequency according to (
2.57
)is
r
107,130
1,000
1
2
p
f
0
¼
¼ 1
:
6511
=
s
:
2.2.4.3 Transverse Waves
A short-time local (lateral) deflection moves as a wave along the wire rope. Czitary
(
1931
) investigated these waves theoretically and he pointed out that the tensile
force of a wire rope can be calculated by measuring the wave running time.
According to Zweifel (
1961
) the velocity of a transverse wave is
s
g
S
q
½1
þ
EI
S
ð
2
p
k
Þ
2
t ¼
:
ð
2
:
61
Þ
In this S is the rope tensile force in N;
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