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S k (
k +
n
nS k 1 (
n
1
)
Q k (
n
1
)=
S k (
n
1
)
which, adding n k
to the both members, becomes:
S k (
k +
n
n k
n k
nS k 1 (
n
1
)
Q k (
n
1
)+
=
S k (
n
1
)+
that is
+
k
1
n k
S k (
n
)=
nS k 1 (
n
1
)
Q k (
n
1
)+
k
nS k 1 (
n k
k
S k (
n
)=
n
1
)
Q k (
n
1
)+
k
+
1
and, by Eq. (5.7):
n
n k
k
k
S k (
n
)=
[(
n
1
)
/
k
+
P k 1 (
n
1
)]
Q k (
n
1
)+
k
+
1
and finally:
n
kn k
1
k
S k (
n
)=
(
n
1
)
+
kP k 1 (
n
1
)
kQ k (
n
1
)+
k
+
1
which corresponds to the statement of the theorem.
5.6.3
Geometrical Progressions
A second case of growth is that of a population where at each step each individual
generates k offspring, therefore at each step the population size increases of its size
multiplied by k (no external effect and no death is considered). In this case, assuming
an initial size equal to 1, the formula providing the population size at generation step
n is:
n
i = 0 k i
G
(
n
)=
.
We prove that
k n
1
1 .
In fact, the proof of this equation is the following:
G
(
n
)=
k
n + 1
i = 1 k i
n
i = 0 k i
k n + 1
kG
(
n
)
G
(
n
)=
=
1
that is,
k n + 1
G
(
n
)(
k
1
)=
1
 
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