Java Reference
In-Depth Information
271
Figure 9
Debugging the
Word
Constructor
At this point, inspecting
i
and
j
shows that
i
is 0 and
j
is 4. That makes senseȌ
there were no punctuation marks to skip. So why is
text
being set to
ÑhellÑ
?
Recall that the
substring
method counts positions up to, but not including, the
second parameter. Thus, the correct call should be
text = s.substring(i, j + 1);
This is a very typical off-by-one error.
