Civil Engineering Reference
In-Depth Information
viscous damping small enough to make it oscillate. We assume that x ( t ) is the
displacement of the mass when we initially move it from its stable position and then
release it. We may write
at
xt
( )
=
Ae
cos(2
π
ft
)
for
t
>
0
0
and
xt
( )
=
0 otherwise.
How quickly the motion “dies out” is determined by the constant a and Figure 1.7 shows
a time section where a is 1 s -1 and 50 s -1 , respectively. The amplitude A is set equal to 1.0
and the frequency f 0 is 25 Hz for both curves 1 . The modulus of the Fourier transform will
be
1
2
2
2
2
a
+
4
π
f
Xf
()
=⋅
A
.
2
(
)
2
2
2
2
2
2
2
a
+
4
π
f
f
+
16
π
a
f
0
1.0
0.8
0.6
0.4
0.2
0.0
-0.2
-0.4
-0.6
-0.8
-1.0
0.00
0.05
0.10
0.15
0.20
0.25
Time t (s)
Figure 1.7 Time function of a damped oscillation (see the expression for x(t) above). The constant a is equal to
1 (thin line) and 50 (thick line), respectively.
This expression is shown in Figure 1.8 for the two values of a . It should be noted
that the ordinate scale is logarithmic in contrast to that used in Figure 1.6 . As expected
we do get a very narrow spectrum around f 0 when the system has low damping. Setting a
= 1 s -1 reduces the amplitude to 1/10 of the starting value after a time 2.3 seconds, i.e.
after some 60 periods. When a is 50 s -1 the amplitude is down to 1/10 just after one
period and the spectrum is then much broader.
1
The frequency f 0 will not be independent of the damping of a real system. However, with the chosen variation
in the damping coefficient a the variation in f 0 will be approximately 5%.
 
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