Civil Engineering Reference
In-Depth Information
It could be useful to give an example illustrative of the sound power due to this
bending near field. We shall then make a comparison with the radiated sound power
from a given area of an infinite plate, in conformity with defining the radiation factor.
We envisage this area as a piston having radius
a.
Setting the velocity amplitude equal to
u
0
the radiated sound power will be given by
22
W
=
ρπ
c
a u
0
.
(6.63)
piston
0
0
The task is now to find the radiated sound power due to the near field according to
together with Equation
(6.41)
, we obtain
3
2
⋅
8
ρ
π
cu
00
0
W
=
.
(6.64)
point
3
2
f
c
Equating this sound power with
W
piston
we obtain
22
c
c
0
0
a
=
⋅
≈
0.29
.
(6.65)
2
f
f
π
c
c
Example
The critical frequency
f
c
of a concrete plate, having a thickness of 50 mm, will
be approximately 380 Hz (see
Figure 6.11)
. The radius
a
of the equivalent piston source
will thereby be ≈ 26 cm. Using e.g. an applied force of 10 N (RMS-value) we get from
level
L
W
re 10
-12
watts of 66 dB. Assuming a semicircular radiation centred on the driving
point the sound pressure level
L
p
will be 58 dB at a distance of 1 metre.
In several practical cases, it is important to know the radiated power from the
bending near field, not only when a point force drives the plate, but also equally well
when driven along a line. The latter applies to cases where vibrations are transmitted to a
panel or wall by studs or stiffeners. Corresponding expressions to the ones given in
2
2
2
ρ
F
2
ρ
π
c u
0
A
0
0
0
A
A
W
=
⋅ =
⋅
when
f
<<
f
.
(6.66)
line
c
2
f
m
ω
c
The quantities
F
ℓ
and
ℓ
are the force per unit length and the length of the line,
respectively.
6.4.2.2
Total sound power emitted from a plate
We have already presented an expression giving the total acoustical power emitted from
one
side of a point-excited plate (see Equation
(6.61)
). By inserting the expression for the
mean square velocity, we obtain