Room acoustics - Building Acoustics - page 111

For the case of the one-dimensional standing wave, we named the points where the
sound pressure was zero as nodal points . By analogy, here we shall have nodal planes if
one or more of these indices is zero and the indices will indicate the number of such
planes normal to the x-, y- and z-axis, respectively. That the nodal points have the form
of a plane is a special case due to the example we have chosen, the rectangular room. For
other shapes we shall have other types of geometric surface; we shall call them nodal
surfaces .

4.4.1 The density of eigenfrequencies (modal density)

Concerning measurements in building acoustics, such as sound insulation, sound
absorption, sound power etc. the eigenfrequencies per se are not particularly important.
The relative density, i.e. the number of eigenfrequencies within a given bandwidth, is,
however, of crucial importance for measurement accuracy. By analogy to the calculation
of the modal density for a plate (see section 3.7.3.5), we may develop a wave number
diagram having the shape as the octant of a sphere. Summing up the number of “points”
or eigenfrequencies N below a given frequency f , we arrive at the following approximate
expression

3 2

4 π f π f L f

N ≈ ⋅ + V ⋅ + S ,

(4.13)

3 2

3 c 4 c 8 c

0

0 0

where V , S and L are the room volume, the total surface area of the room and the total
length of the edges, respectively. Differentiating this expression with respect to
frequency we arrive at the following approximate expression for the modal density

2

Δ N 4 π f π f L

≈ ⋅ + V ⋅ + S .

(4.14)

3 2

Δ f c 2 c 8 c

0

0 0

As seen, the first term will be the dominant one at higher frequencies, and in the
literature one often finds this term alone. This certainly has the advantage of requiring
the room volume only, but this practice may introduce large errors at low frequencies.

Example An ordinary sitting room in a dwelling with dimensions L x ⋅ L y ⋅ L z equal to
6.2 ⋅ 4.1 ⋅ 2.5 metres, gives us a floor area of 25.4 m 2 and a volume of 63.6 m 3 . Choosing
a frequency of 100 Hz, Equation (4.14) gives us Δ N /Δ f equal to 0.361. If we measure
using one-third-octave bands filters, at centre frequency 100 Hz we get a bandwidth Δ f ≈
0.23⋅100 = 23 Hz. We will then get 23⋅0.361 ≈ 8 eigenfrequencies inside this band,
which compares well with an exact calculation giving seven eigenfrequencies. If we just
use the first term we will get five eigenfrequencies. However, going up in frequency the
first term will become dominant. Keeping a fixed bandwidth of 23 Hz and moving up to
1000 Hz, we expect to find approximately 500 eigenfrequencies (the first term alone
gives 470). Using a one-third-octave filter we arrive at approximately 5000
eigenfrequencies inside the band.