Chemistry Reference
In-Depth Information
We have in general [cf. Eq.(160)],
t
dt 2 t 1
0
kT
α
1
1
2 ( t )
2 γ 2
=
t 2 ) 2 α F ( t 1 ) F ( t 2 ) dt 1
( α
1)
( t 1
0
For the ramped gradient shape [cf. Eq. (70)],
t 1
dt
G t
δ
F ( t 1 )
=
(171)
δ
0
so that
Gt 1
Gt 2
Gt 1
2 δ
Gt 2
2 δ
F ( t 1 ) F ( t 2 ) θ ( t 1 ) θ ( t 2 )
=
(172)
Thus,
2 ( t )
Gt 2
dt 2 t 2
0
2 δ
2 kTγ 2
α
Gt 2
2 δ
dt 1
( α
1
=
( t 2
t 1 ) 2 α
1)
0
Gt 1
Gt 1
2 δ
(173)
that is
2
2
( t )
2 G 2 (2 δ ) 2 + α α ( α
+
3)
=
(174)
(5
+
α )
When α
1, the expression becomes the normal diffusion case, Eq. (70).
Now for the triangular configuration,
dt 2 t 2
0
2
Gt 2
δ
t 1 ) 2 α Gt 1
δ
2
2 kTγ 2
α
dt 1
( α
1
2 =
(175)
1)
( t 2
δ
δ
0
0
δ
2 2 δ =
Gt 2
2
dt 2
4
+
2 kTγ 2
α
2 t 2
δ
2
δ
2
t 2
t 1 ) 2 α Gt 1
4
+
dt 1
( α
1
2 t 1
δ
2
×
(176)
1)
( t 2
2
δ
2
2
Gt 1
2
dt 2
3 δ
2
2 kTγ 2
α
6
δ
t 1
2
2 =
4
+
3 δ
δ
δ
t 2
t 1 ) 2 α Gt 1
2
(177)
6
δ 4
dt 1
( α
1
t 1
×
+
( t 2
1)
2
δ
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