Chemistry Reference
In-Depth Information
S,...,S, and the energy levels of the magnetic molecule are given by
Dm 2
Bm 4
ε m =−
B H z m
(141)
The transition frequency for a pair of levels is
m m
m D
m 2
m 2 B
B H z
(142)
ε m =− m
ω mm =
ε m
+
+
+
+
m (levels on different sides of the barrier cre-
ated by the uniaxial anisotropy) defines the resonance values of the longitudinal
field H z . For the generic model of molecular magnets with B
Condition
ω mm =
0 for m/
=
=
0 the latter are
given by
B H z =
kD,
k
=
0 ,
±
1 ,
±
2 ,...
(143)
For these fields, all levels in the right well
m =−
m
k
(144)
are at resonance with the corresponding levels in the left well m< 0 . For the
realistic model with B> 0 , the field creating resonances between low-lying levels
with large m 2
m 2 is greater than the resonance fields for high levels. Transverse
anisotropy and transverse field H x that enter H A result in the tunneling under the
barrier and tunneling splitting of the resonant levels m, m . Note that the resonance
condition, Eq. (143) does not depend on the transverse field. To the contrary, for
B/
+
=
0 the resonance condition depends on the transverse field.
For Mn 12 used in illustrations below, we adopt the values D/k B =
0 . 548 K and
10 3 K [14-16] that make up the barrier of 66 K. Here H A in Eq.
(140) can contain second- and fourth-order transverse anisotropy,
B/k B =
1 . 1
×
E S x
S y
H A =
C ( S 4
S 4
+
+ +
)
(145)
10 5
For Mn 12 , C/k B =
0 in the ideal case be-
cause of the tetragonal symmetry of the crystal. However, it was shown [16] that
local molecular environments of Mn 12 molecules have a twofold symmetry and
rotated by 90 for different molecules. Although on average the fourfold sym-
metry of the crystal is preserved, it gives rise to nonzero E that will be set to
E/k B =
3
×
K [14-16], whereas E
=
10 3 K.
The spin Hamiltonian of molecular magnets can be easily numerically diago-
nalized to yield eigenstates
2 . 5
×
|
α
and transition frequences ω αβ ,α,β
=
1 , .., 2 S
+
1 .
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